Assuming you mean Fixed Point and not Floating Point, what data representation are you supposed to use for this problem?ver_mathstats said:
We did not learn one's complement or two's complement in this particular class, so neither of those.berkeman said:
The problem states "double precision" which is floating point, specifically it is the binary64 implementation of IEEE754: https://en.wikipedia.org/wiki/Double-precision_floating-point_format.berkeman said:
Single precision numbers use 32 bits to represent a floating-point number, while double precision numbers use 64 bits. This allows for a larger range of numbers and increased precision in calculations for double precision numbers.
Double precision numbers are stored using the IEEE 754 standard, which uses a sign bit, an exponent, and a significand (also known as mantissa) to represent the number. The sign bit determines if the number is positive or negative, the exponent specifies the size of the number, and the significand holds the digits of the number.
No, double precision numbers have a limited number of bits and therefore cannot accurately represent all real numbers. They can only approximate real numbers within a certain range and with a certain level of precision.
The advantage of using double precision numbers is that they can handle a wider range of numbers and provide more accurate results in calculations. This is especially important in scientific computing where precision and accuracy are crucial.
One drawback of using double precision numbers is that they require more memory and processing power compared to single precision numbers. This can impact the performance of programs that heavily use double precision calculations.