- #1
eMac
- 17
- 0
1.Find the vertical and horizontal asymptotes (if any), intervals of increase and decrease, local maximum and minimum values, intervals of concavity and inflection points for f(x) = 1 / (L - x^1/2)
3. I found the vertical asymptote to be "x=0" , I found the horizontal asymptote to be "y=0"
So to find intervals of increase and decrease you have to find the derivative, which I found to be 2*x/(L^2-2*x^2*L+x^4) from here I plugged in values.
To find local maximum and minimum values you have to find the second derivitive, which I found to be (2*L+6*x^2)/(L^3-3*x^2*L^2+3*x^4*L-x^6)
Then I came to the conclusion that there is no inflection point because there are no local maximum's meaning no change in concavity
I'm not sure if I did these right, would really appreciate some help, thanks.
3. I found the vertical asymptote to be "x=0" , I found the horizontal asymptote to be "y=0"
So to find intervals of increase and decrease you have to find the derivative, which I found to be 2*x/(L^2-2*x^2*L+x^4) from here I plugged in values.
To find local maximum and minimum values you have to find the second derivitive, which I found to be (2*L+6*x^2)/(L^3-3*x^2*L^2+3*x^4*L-x^6)
Then I came to the conclusion that there is no inflection point because there are no local maximum's meaning no change in concavity
I'm not sure if I did these right, would really appreciate some help, thanks.