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If I were to attach a sphere (mass M radius R) to the end of a thin rod (mass m length L), the end of the rod being attached to a pivot, how would I calculate the moment of inertia for that object?
The rod: 1/3 mL^2
The sphere: 2/5 MR^2
The object: 1/3 mL^2 +2/5 MR^2 + M(L+R)^2 ?
Thanks for the help in advance...
The rod: 1/3 mL^2
The sphere: 2/5 MR^2
The object: 1/3 mL^2 +2/5 MR^2 + M(L+R)^2 ?
Thanks for the help in advance...