Conceptual problem with perturbation theory

In summary, the conversation discusses the use of the Hamiltonian in one dimension with a weak term, W, and the application of perturbation theory. The problem arises when trying to calculate the eigenvalues and eigenfunctions of H0, and the solution involves setting the system in an imaginary potential well with a width, L. However, the value of L is unknown and can greatly affect the energies and wave functions. If L is set to infinity, the wave function becomes a Fourier transform of the continuous variable p.
  • #1
eljose
492
0
-Ok..Let,s be the Hamiltonian [tex] H=H_0 +W [/tex] in one dimension where W is a "weak" term so we can apply perturbation theory.

-The "problem" comes when we need to calculate the eigenvalues and eigenfunction of H0 of course we set the system in an "imaginary potential well of width L" so we have the set of eigen-values-functions:

[tex] E_n =P^{2}/2m [/tex] [tex] p=(n\pi \hbar)/L [/tex] [tex] \Phi(x) =e^{in\pi x/L} [/tex]

the problem is...what is the value of L?...so when doing calculations..what,s the value of the width of our "imaginary" well..if we set L--->oo then the Energies and Wave functions tend all to 0.
 
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  • #2
eljose said:
-Ok..Let,s be the Hamiltonian [tex] H=H_0 +W [/tex] in one dimension where W is a "weak" term so we can apply perturbation theory.

-The "problem" comes when we need to calculate the eigenvalues and eigenfunction of H0 of course we set the system in an "imaginary potential well of width L" so we have the set of eigen-values-functions:

[tex] E_n =P^{2}/2m [/tex] [tex] p=(n\pi \hbar)/L [/tex] [tex] \Phi(x) =e^{in\pi x/L} [/tex]

the problem is...what is the value of L?...so when doing calculations..what,s the value of the width of our "imaginary" well..if we set L--->oo then the Energies and Wave functions tend all to 0.

For one, when you set [itex]L\rightarrow\infty[/itex], [itex]\Phi_n[/itex] does not tend to zero, it tends to 1, because that's a complex exponential,

[tex]e^{in\pi\tfrac{x}{L}}=\cos\left(n\pi\tfrac{x}{L}\right)+i\sin\left(n\pi\tfrac{x}{L}\right)[/tex].

Since each [itex]\Phi_n(x) =e^{in\pi x/L}[/itex] is linearly dependant you can write the wave-function as a Fourier series with these functions as a basis. If L tends to infinity your sum of plane wave bases becomes a Fourier transform of the continuous variable p, rather than the discrete sum of p's (or n's). This is just the same procedure one goes through in generalising the Fourier series of functions with finite period to those with infinite period.
 
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  • #3

This is a valid concern when using perturbation theory. In order for perturbation theory to work, the perturbation term W must be "small" compared to the unperturbed Hamiltonian H0. This means that the perturbation term should be much smaller than the energy scales of the system. In the case of the imaginary potential well, the width L determines the energy scale of the system. If L is too large, then the perturbation term W may not be small enough and perturbation theory may not be valid.

One solution to this problem is to choose a value of L that is physically reasonable for the system being studied. For example, if the system is a physical well with a certain width, then that width can be used in the calculations. Another approach is to use a variational method, where the width L is treated as a parameter that is optimized to give the best approximation to the true solution.

Overall, the conceptual problem with perturbation theory is that it relies on the perturbation term being small, and this may not always be the case in realistic systems. Careful consideration must be given to choosing appropriate values for parameters such as L in order to ensure the validity of perturbation theory.
 

FAQ: Conceptual problem with perturbation theory

What is perturbation theory?

Perturbation theory is a mathematical tool used to approximate solutions to problems that cannot be solved exactly. It involves breaking down a complex problem into smaller, more manageable parts and then using mathematical techniques to solve each part separately. The solutions to the smaller parts are then combined to give an approximate solution to the original problem.

What is the conceptual problem with perturbation theory?

The main conceptual problem with perturbation theory is that it assumes the perturbation (small disturbance) is small enough to be ignored. However, in many real world situations, the perturbation may not be small enough to be ignored, leading to inaccurate approximations.

How does perturbation theory address the conceptual problem?

Perturbation theory addresses the conceptual problem by using higher-order approximations. By including more terms in the approximation, the accuracy of the solution can be improved. However, this can also lead to more complex calculations and may not always give an exact solution.

What are some applications of perturbation theory?

Perturbation theory has many applications in physics, engineering, and other sciences. It is commonly used in quantum mechanics, fluid dynamics, and celestial mechanics to approximate solutions to complex problems. It is also used in fields such as economics and biology to model and analyze systems with small disturbances.

Are there any alternative methods to perturbation theory?

Yes, there are alternative methods to perturbation theory, such as numerical methods and variational methods. These methods may be more accurate for certain types of problems, but they also have their own limitations. In some cases, a combination of different methods may be used to obtain a more accurate solution.

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