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rwx1606
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Homework Statement
If a person stands on a level ground and throws a baseball, we say that a "launch angle" of 45 degrees will make the baseball travel farthest before it lands (ignoring air resistance). That is, the baseball has a maximum range when thrown at a 45 degree angle. But suppose that instead of standing on level ground, you are standing on the edge of a cliff when you throw the baseball. Will the best angle in this case be less than 45, equal to 45, or greater than 45 degrees?
Homework Equations
The Attempt at a Solution
My graduate student instructor said something about if the ball is just thrown horizontally off the cliff then that would give you the max range, but I don't really understand what's going on here. I know throwing up at an angle gives the ball more air time, and I've plugged in numbers for fun to help. I found that I do get a greater range when the ball is thrown at an angle less than 45 but only for bigger heights. What I did was use 20meters and 100 meters as the cliff's height. Only using 100meters did I found that the range was greater with just an initial horizontal velocity as opposed to throwing it at an angle less than 45.Can someone explain to me why?