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unrstudent
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1. Homework Statement
Calculate the magnitude and direction of the Coulomb force on each of the three charges shown in Figure P15.10.
http://www.webassign.net/sf5/p15_10.gif
thats 3 cm if its to small to see.
6.00 µC charge Correct answer 46.76N
Magnitude to Left
1.50 µC charge Correct answer 157.325N
Magnitude to Right
-2.00 µC charge correct answer 110.565N
Magnitude to leftF = K|q1||q2|/r^2
I have it, but I don't know why it worksThis what I have
F13=43.14N
F23=67.425N
F12=89.9N
the 6.00 C made sense Fnet=|-89.9+43.14|
The following were completely different
1.50 C should be Fnet=|-89.9+67.425|
but it not instead, I add the two to get 157.325
this does not make sense because unless 6.00 c was negative, the charges should cancel out like they did in first oneBasically, I got the exact opposite magnitudes and direction, i don't understand
Calculate the magnitude and direction of the Coulomb force on each of the three charges shown in Figure P15.10.
http://www.webassign.net/sf5/p15_10.gif
thats 3 cm if its to small to see.
6.00 µC charge Correct answer 46.76N
Magnitude to Left
1.50 µC charge Correct answer 157.325N
Magnitude to Right
-2.00 µC charge correct answer 110.565N
Magnitude to leftF = K|q1||q2|/r^2
I have it, but I don't know why it worksThis what I have
F13=43.14N
F23=67.425N
F12=89.9N
the 6.00 C made sense Fnet=|-89.9+43.14|
The following were completely different
1.50 C should be Fnet=|-89.9+67.425|
but it not instead, I add the two to get 157.325
this does not make sense because unless 6.00 c was negative, the charges should cancel out like they did in first oneBasically, I got the exact opposite magnitudes and direction, i don't understand
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