- #1
randomcat
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Suppose that there are 2 apple trees. Tree A and tree B.
A produces 0.7 of the farm's apples. And B produces 0.3.
Out of the apples that tree A produces, 0.15 are bad. For B, 0.05 are bad.
One package of goodies contains 3 apples.
Given this information, what is the P(Tree A| at least one bad apple in the package)
Okay, so here's what I tried.
Probability of at least 1 bad apple in the package from tree A is:
x=0.7*(1-(0.85)^3)
Probability of at least 1 bad apple in the package from tree B is:
y=0.3*(1-(0.95)^3)
Then P(Tree A| at least one bad apple in the package) = x/(x+y) = 0.863
Does this seem right? Any help would be greatly appreciated.
A produces 0.7 of the farm's apples. And B produces 0.3.
Out of the apples that tree A produces, 0.15 are bad. For B, 0.05 are bad.
One package of goodies contains 3 apples.
Given this information, what is the P(Tree A| at least one bad apple in the package)
Okay, so here's what I tried.
Probability of at least 1 bad apple in the package from tree A is:
x=0.7*(1-(0.85)^3)
Probability of at least 1 bad apple in the package from tree B is:
y=0.3*(1-(0.95)^3)
Then P(Tree A| at least one bad apple in the package) = x/(x+y) = 0.863
Does this seem right? Any help would be greatly appreciated.