- #1
vtmvick7
- 2
- 0
confirm my answers on Oscillating Springs??
Can anyone confirm or adjust my answers for problems 12 and 14? Also can someone help me start on problem 13.. Thanks guys I really appreciate the help
012
Find the speed of the block when it is 2.5 cm
from the equilibrium position.
Answer in units of m/s.
013
Find its acceleration at 2.5 cm from the equilibrium position.
Answer in units of m/s2.
014
Find the time it takes the block to move from
x = 0 to x = 2.5 cm.
Answer in units of s.
M= 0.7kg
k= 14.7 N/m
A= 5cm
w= 4.58 rads/s
T= 1.37s
#14: x(t) = 5cm Cos(4.58rads/s*(t))
t= (1/4.58 rads/s) cos^-1 (2.5cm/5cm) = 13.09s??
do I convert it to meters??
#12: E=1/2mv^2 + 1/2kx^2 = 1/2ka^2
1/2(.7)v^2 + 1/2(14.7)(.025m)^2 = 1/2(14.7)(.05m)^2
.35v^2=.0137
v=0.1984m/s
I changed the cm to m, I should have done this right??
Can anyone confirm or adjust my answers for problems 12 and 14? Also can someone help me start on problem 13.. Thanks guys I really appreciate the help
Homework Statement
012
Find the speed of the block when it is 2.5 cm
from the equilibrium position.
Answer in units of m/s.
013
Find its acceleration at 2.5 cm from the equilibrium position.
Answer in units of m/s2.
014
Find the time it takes the block to move from
x = 0 to x = 2.5 cm.
Answer in units of s.
Homework Equations
M= 0.7kg
k= 14.7 N/m
A= 5cm
w= 4.58 rads/s
T= 1.37s
The Attempt at a Solution
#14: x(t) = 5cm Cos(4.58rads/s*(t))
t= (1/4.58 rads/s) cos^-1 (2.5cm/5cm) = 13.09s??
do I convert it to meters??
#12: E=1/2mv^2 + 1/2kx^2 = 1/2ka^2
1/2(.7)v^2 + 1/2(14.7)(.025m)^2 = 1/2(14.7)(.05m)^2
.35v^2=.0137
v=0.1984m/s
I changed the cm to m, I should have done this right??