Confirming the domain for this integral

In summary, the question asked for the probability of X+Y being greater than 1, given that 0<=x<=y<=1. To solve this, the domain of the integral had to be found, which was visualized through graph sketches of 0<x<y<1 and x+y>1. Combining these graphs showed that the solution was a triangle in the top quarter of a 1x1 square. However, there were multiple ways to approach the integral, such as multiplying by 2 and splitting it into two triangles or simplifying it by integrating over the domain of 0 to 1 and dividing by 4.
  • #1
fateswarm
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Homework Statement



In a Probabilities question it was known that 0<=x<=y<=1.

It was asked what is the P(X+Y>1).

So I had to find the domain for that integral first.

Homework Equations



The Attempt at a Solution



I started with a graph sketch for 0<x<y<1 which gave half of the 1X1 square, the north-west triangle.

Then I did a graph sketch of x+y>1 which gave the north-east trangle of the half of the 1X1 square.

Combining those I get a triangle at the top corresponding to a quarter of it all.

So, is it right to assume that it is wrong to do it directly on one integral without splitting it in two triangles?

My current solution is that the integral must by multiplied by 2 and be done in the domain of 0.5 to 1 for dy externally of the integral and inside 1-y to 0.5 for dx, or equivalently, 0 to 0.5 for dx externally, and 1-x to 1 for dy internally (each integral multiplied by 2) (plus two other solutions representing the other triangle).
 
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  • #2
But to make it simpler, I think that the integral should be done in the domain of 0 to 1 for both dx and dy, but then divided by 4.Which is the correct solution?
 

FAQ: Confirming the domain for this integral

What is the purpose of confirming the domain for an integral?

The domain of an integral represents the range of values for which the function is defined. Confirming the domain ensures that the integral is well-defined and avoids any mathematical errors or inconsistencies.

How can I determine the domain of an integral?

The domain of an integral can be determined by examining the function and identifying any restrictions or limitations. This may include avoiding division by zero, negative values under a square root, or any other restrictions specified in the problem.

What happens if I include values outside of the domain in an integral?

If values outside of the domain are included in an integral, the result may be undefined or may give an incorrect answer. It is important to always confirm the domain and only include values within that range when calculating an integral.

Can the domain of an integral change?

Yes, the domain of an integral can change depending on the function being integrated and any restrictions or limitations. It is important to always check the domain in each individual integral problem.

Are there any common mistakes when confirming the domain for an integral?

Yes, some common mistakes include forgetting to check for restrictions or limitations, not considering negative values under a square root, and not recognizing when the domain may be extended. It is important to carefully examine the function and confirm the domain to avoid these mistakes.

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