- #1
Petrus
- 702
- 0
Hello MHB,
I would like if someone could confirmed if I did understand correct.
In a ON-system we don't use \(\displaystyle u*v=|u||v|\cos\theta\) cause In a ON-system the \(\displaystyle \theta=\frac{\pi}{2}\) so \(\displaystyle \cos(\frac{\pi}{2})=0\)
Regards
\(\displaystyle |\pi\rangle\)
I would like if someone could confirmed if I did understand correct.
In a ON-system we don't use \(\displaystyle u*v=|u||v|\cos\theta\) cause In a ON-system the \(\displaystyle \theta=\frac{\pi}{2}\) so \(\displaystyle \cos(\frac{\pi}{2})=0\)
Regards
\(\displaystyle |\pi\rangle\)