- #1
SnowOwl18
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Ok I've been trying this problem :
---A 21.0kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring constant k=14.0N/m. A 2.10×10-2kg bullet traveling with a speed of 530m/s embeds itself in the block. What is the amplitude of the resulting simple harmonic motion? Recall that the amplitude is the maximum displacement from equilibrium.----
And I thought I could use the equation (1/2)mv^2 = (1/2)kA^2 ...but I got the answer wrong...and the hint says to first use conservation of momentum, and then conservation of energy. It seems like i couldn't do that, since it seems like I don't have enough information. Any help? Thanks :)
---A 21.0kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring constant k=14.0N/m. A 2.10×10-2kg bullet traveling with a speed of 530m/s embeds itself in the block. What is the amplitude of the resulting simple harmonic motion? Recall that the amplitude is the maximum displacement from equilibrium.----
And I thought I could use the equation (1/2)mv^2 = (1/2)kA^2 ...but I got the answer wrong...and the hint says to first use conservation of momentum, and then conservation of energy. It seems like i couldn't do that, since it seems like I don't have enough information. Any help? Thanks :)