Confusion in using the continuity equation here

AI Thread Summary
Assuming "Properties in the tank are uniform, but time-dependent" leads to the validity of (DmDt)sys=0 because the mass of the system remains invariant over time, despite changes in the control volume. The system encompasses all matter inside, entering, or exiting the control volume, while the mass within the control volume changes as time progresses. The first integral represents the instantaneous mass in the control volume, and the second integral accounts for mass flow out of the container. This distinction clarifies that the perceived change in mass does not contradict the continuity equation. Understanding these concepts is crucial for correctly applying the continuity equation in fluid dynamics.
tracker890 Source h
Messages
90
Reaction score
11
Homework Statement
I feel that the mass within the system changes over time, but this perception contradicts the solution.
Relevant Equations
continuity equation
Q: Why does assuming "Properties in the tank are uniform, but time-dependent" lead to the validity of
(DmDt)sys=0? Doesn't the mass within the system change over time?
reference.
1700656597283.png
 
Physics news on Phys.org
tracker890 Source h said:
Homework Statement: I feel that the mass within the system changes over time, but this perception contradicts the solution.
Relevant Equations: continuity equation

Q: Why does assuming "Properties in the tank are uniform, but time-dependent" lead to the validity of
(DmDt)sys=0? Doesn't the mass within the system change over time?
reference.
View attachment 335945
The mass of the system is the total mass, i.e. what’s inside and what’s outside the control volume at a particular time. It is invariant (at least in classical physics?). at ##t=0## all of the system is inside the control volume, as time progresses some portion of the system is outside. That ∫ on the left (unsteady) represents what portion of the system is inside (only) the control volume at a particular time.

Summarizing: The system is not the control volume. The system is the stuff (matter) inside the control volume, on its way into the control volume, or what has left the control volume.
 
Last edited:
  • Like
Likes tracker890 Source h and TSny
To add a little to @erobz, the first integral ##\int_{\small CV}\rho dV## is the instantaneous mass within the control volume. This mass changes with time. So, ##\frac{\partial}{\partial t}\int_{\small CV}\rho dV## represents the rate of change of mass within the tank. The second integral represents the rate at which mass is flowing out through the neck of the container.
 
  • Like
Likes tracker890 Source h, Chestermiller and erobz
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top