- #1
mrmudd
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I'm having some trouble getting my head around the scale at which capillary flow and contact line dynamics are important. In the simple case of liquid rise in a capillary tube, a smaller tube will allow for greater rise since a larger height is required to achieve an equal weight of the liquid column to balance the capillary pressure. That's totally fine and makes complete sense.
My problem is when gravity is removed from the problem. Consider now Washburn's equation where the penetration length L is proportional to the radius of the capillary tube. This is where I start to get to confused. I can understand that at small length scales, viscous dissipation will be greater thus slowing down the flow. However, if we assume a very large pipe, say 0.5 meter radius; the rate at which the pipe is filled with liquid due solely to the contact line is no way going to be faster than 1 mm radius tube. I suppose there is a limiting length scale above which Washburn's equation cannot be applied; however, I cannot seem to find it anywhere.
On this note, the scale at which a contact line drives the flow is elusive to me. Consider in zero gravity, a container filled with fine powder and a tiny water droplet. Obviously, the a hydrophilic contact angle will result in the imbibition of water into the pore space between the powder and that effect will dominate the final configuration of liquid in the powder. Now if we scale up the exact problem (still in zero gravity) to something like a swimming pool filled with boulders. The contact angle between the water and the boulder would play very little effect in driving any flow into the space between the boulders. So there has to be some way of quantifying the scale at which contact angles play an important roll. It must include the mass of liquid and surface tension, right?
My problem is when gravity is removed from the problem. Consider now Washburn's equation where the penetration length L is proportional to the radius of the capillary tube. This is where I start to get to confused. I can understand that at small length scales, viscous dissipation will be greater thus slowing down the flow. However, if we assume a very large pipe, say 0.5 meter radius; the rate at which the pipe is filled with liquid due solely to the contact line is no way going to be faster than 1 mm radius tube. I suppose there is a limiting length scale above which Washburn's equation cannot be applied; however, I cannot seem to find it anywhere.
On this note, the scale at which a contact line drives the flow is elusive to me. Consider in zero gravity, a container filled with fine powder and a tiny water droplet. Obviously, the a hydrophilic contact angle will result in the imbibition of water into the pore space between the powder and that effect will dominate the final configuration of liquid in the powder. Now if we scale up the exact problem (still in zero gravity) to something like a swimming pool filled with boulders. The contact angle between the water and the boulder would play very little effect in driving any flow into the space between the boulders. So there has to be some way of quantifying the scale at which contact angles play an important roll. It must include the mass of liquid and surface tension, right?
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