- #1
NotMrX
- 97
- 0
If a electron slows down while moving due to an electric field we would say the potential decreases. If a proton slows down while moving into an electric field does potential increase? I am confused because:
[tex]\Delta KE=q\Delta V=\frac{m(v^2_f-v^2_i)}{2}[/tex]
but I would get opposite signs for the voltage in those cases that I thought I was supposed to.
[tex]\Delta KE=q\Delta V=\frac{m(v^2_f-v^2_i)}{2}[/tex]
but I would get opposite signs for the voltage in those cases that I thought I was supposed to.