- #1
astrololo
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Homework Statement
I have : (x)^2+(2xy)+y^2+2(2)^(1/2)x−2(2)^(1/2)y+4=0
Now when I use the rotation formulas I get : y'=(x'^2)/2 + 1
But I don't know if this makes sense...
Homework Equations
tan2β=B/(A−C)x=x'cos β - y'sin β
y=x'cos β + y'sin β
The Attempt at a Solution
We know that β= pi/4 because B/(A−C) tends towards infinity.
So we replace pi/4 in
x=x'cos β - y'sin β
y=x'cos β + y'sin β
and put those in the long equation and simplify. Which gives us y'=((x'2)/2)+1
Does this make sense my answer
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