- #1
putsub12jk
- 2
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hello,
putsub12jk said:hello,
putsub12jk said:you can either express the velocity vector is terms the displacement of the square conducting loop and time, alternatively it would also be good to state the direction of the velocity vector itself i.e. in the +y direction maybe in the step before in your workings. So you can state v sub y hat cross B sub x hat. And yes your direction is also correct as it follows Lenz's Law.