- #1
peripatein
- 880
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Hi,
A satellite with mass m orbits a planet of mass M in a circular path with radius r and velocity v. Due to some internal technical failure, the satellite breaks into two, similar parts with mass m/2 each. In the satellite's frame of reference, it appears the two parts move radially, in opposite directions, along the line connecting the original satellite and the planet's center, each with velocity v0/2. I am expected to show that right after the technical failure, each of the two parts has a total energy equal to -3GM/16r and angular momentum equal to (m/2)√(GMr), wrt the planet's center.
The total energy of each of the two parts should be, I believe: Etot = mv02/16 - GmM/(2r). Now, isn't angular momentum preserved despite the failure? However, why isn't the angular momentum zero if the two parts are moving in opposite directions?
Homework Statement
A satellite with mass m orbits a planet of mass M in a circular path with radius r and velocity v. Due to some internal technical failure, the satellite breaks into two, similar parts with mass m/2 each. In the satellite's frame of reference, it appears the two parts move radially, in opposite directions, along the line connecting the original satellite and the planet's center, each with velocity v0/2. I am expected to show that right after the technical failure, each of the two parts has a total energy equal to -3GM/16r and angular momentum equal to (m/2)√(GMr), wrt the planet's center.
Homework Equations
The Attempt at a Solution
The total energy of each of the two parts should be, I believe: Etot = mv02/16 - GmM/(2r). Now, isn't angular momentum preserved despite the failure? However, why isn't the angular momentum zero if the two parts are moving in opposite directions?