- #1
sjcorona
- 8
- 0
Two children are playing a game in which the try to hit a small box on the floor with a marble fired from a spring loaded gun mounted on a table. The target box is horizontal distance D=2.20 m from the edge of the table. Bobby compresses the spring 0.011m but the center of the marble falls 0.27 m short of the center of the box How far should Rhoda compress the spring to score a direct hit? Assume that neither the spring nor ball encounters friction in the gun.
So I know that the ball will leave the gun with initial kinetic energy of 1/2mv^2 = the 1/2 k Δx^2 of the springs potential energy. I tried isolating velocity and using that in my kinematic equation d=v(t)+1/2at^2 and solved for time thinking that maybe I could find the height of the table and find the right velocity from there then work backwards to spring potential energy, but that didn't work because I don't know k or m and am not sure if I as n the right track
So I know that the ball will leave the gun with initial kinetic energy of 1/2mv^2 = the 1/2 k Δx^2 of the springs potential energy. I tried isolating velocity and using that in my kinematic equation d=v(t)+1/2at^2 and solved for time thinking that maybe I could find the height of the table and find the right velocity from there then work backwards to spring potential energy, but that didn't work because I don't know k or m and am not sure if I as n the right track