Conservation of momentum and velocity question

In summary, The problem involves a stone box being supported by two steel cylinders with a constant force applied. The goal is to determine the velocity of the stone box when one cylinder has reached the end of the box. One approach is to use the circumference of a circle to find the distance needed for the cylinder to reach the end, and then using F=ma to find the acceleration of the box in the x direction. From there, the total work formula can be used to calculate the velocity of the box. However, the acceleration in the x direction is not equal for the cylinders and the box. The formula used for this problem is total work-.5mv^2+.5*I*(omega)^2, and a relationship between velocity and angular
  • #1
affordable
6
0

Homework Statement




The 1000N stone box is supported by
two steel cylinders A and B at 100N each. The system is at rest
in the position shown when the constant
force P = 100N is applied.

Determine the velocity of the stone box C when cylinder A
has reached the left corner of the box.

http://img801.imageshack.us/i/unledom.jpg/

Homework Equations





The Attempt at a Solution



Ugh. It logged me out, so my explanation will be pretty weak.

What I did was use the circumference of a circle as 20/(30pi) as the distance needed to get the cylinder to the end. I used F=ma to find the acceleration of the box in the x direction is 1/10 in/sec^2.

From here, I'm unsure. I assume that this is a momentum problem that transfers energy to the cylinders, but I'm not for sure which formula to use.

I'm thinking about using total work-.5mv^2+.5*I*(omega)^2.

Would the acceleration in the x direction be equal for the cylinders and the box?
 
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  • #2
hi affordable! :smile:

(have an omega: ω and try using the X2 icon just above the Reply box :wink:)
affordable said:
Would the acceleration in the x direction be equal for the cylinders and the box?

nooo :redface:

what are the speeds of the top middle and bottom of the cylinder? :wink:
I'm thinking about using total work-.5mv^2+.5*I*(omega)^2.

that's the one!

now plug in a formula relating v and ω, and solve :smile:
 

FAQ: Conservation of momentum and velocity question

What is conservation of momentum and velocity?

Conservation of momentum and velocity is a fundamental law in physics that states that the total momentum of a closed system remains constant over time, regardless of any external forces acting upon it. This means that the total mass and velocity of the system will remain the same, even if individual objects within the system experience changes in momentum.

Why is conservation of momentum and velocity important?

Conservation of momentum and velocity is important because it allows us to predict the behavior of objects in a closed system. By understanding this principle, we can make accurate predictions about the motion of objects, such as the trajectories of planets in orbit or the movement of particles in a chemical reaction.

What is the equation for conservation of momentum and velocity?

The equation for conservation of momentum and velocity is:

M1V1 + M2V2 = M1V1' + M2V2'

where M1 and M2 are the masses of two objects, V1 and V2 are their initial velocities, and V1' and V2' are their final velocities.

How is conservation of momentum and velocity related to Newton's laws of motion?

Conservation of momentum and velocity is related to Newton's laws of motion, specifically the third law which states that for every action, there is an equal and opposite reaction. This means that when two objects collide, the total momentum of the system remains constant, as the force exerted by one object on the other is equal and opposite to the force exerted by the other object.

Are there any real-life applications of conservation of momentum and velocity?

Yes, there are many real-life applications of conservation of momentum and velocity. For example, it is used in sports such as billiards and pool, where the conservation of momentum is crucial in predicting the paths of the balls after they collide. It is also important in rocket propulsion, where the conservation of momentum allows for efficient movement through space. Additionally, it is used in car safety design, as understanding the conservation of momentum can help engineers design safer vehicles that can better withstand collisions.

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