Conservation of Momentum (Ch 7-9, Q6)

In summary, when a stationary bomb explodes in space, the net force due to gravity is zero Newtons. This means that the fragments will continue to move indefinitely along straight paths. The velocity of each fragment will be equal, and the sum of their kinetic energies will be zero, as they have lost their kinetic energy in the explosion. The conservation of momentum still applies, as the vector sum of the linear momenta of the fragments must be zero.
  • #1
gcombina
157
3

Homework Statement


A stationary bomb explodes in space breaking into a number of small fragments. At the location of the explosion, the net force due to gravity is zero Newtons. Which one of the following statements concerning this event is true?
(a) Kinetic energy is conserved in this process.

(b) The fragments must have equal kinetic energies.

(c) The sum of the kinetic energies of the fragments must be zero.

(d) The vector sum of the linear momenta of the fragments must be zero.

(e) The velocity of anyone fragment must be equal to the velocity of any other fragment.

Homework Equations


Conservation of Momentum
(mv) before = mv (after)

The Attempt at a Solution



(a) Kinetic energy is conserved in this process.
This is a NO, because Kinetic energy isn't conserved, the energy is lost
(b)
The fragments must have equal kinetic energies
I assume the fragments do not longer have Kinetic energy but Potential energy so its a NO
(c)
The sum of the kinetic energies of the fragments must be zero.
Fragments do not longer have Kinetic energy as they are stationary, they have potential energy (I have no clue if this reasoning is correct) so the answer is NO
(d) The vector sum of the linear momenta of the fragments must be zero.
mass and velocity = 0 so Yes
(e) The velocity of anyone fragment must be equal to the velocity of any other fragment.
The velocity is ZERO so they all have the same velocity so the answer is YES to this too (Is this correct? like some fragments can be having a velocity of 0 and others can have some movement still)
 
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  • #2
You need to rethink what is going on here. Before the bomb explodes it is sitting stationary, so no kinetic energy. After it explodes, whatever energy powers the bomb (chemical, atomic,...) is turned into heat and kinetic energy of the fragments. The fragments scatter in all directions. Because the explosion takes place in space far from any large gravitational forces and without any friction to slow anything down, the fragments will all continue to travel indefinitely along straight paths.
 
  • #3
I see, that is why they said 0 gravity...brb
 

FAQ: Conservation of Momentum (Ch 7-9, Q6)

1. What is conservation of momentum?

The conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system remains constant. This means that the total momentum before a collision or interaction is equal to the total momentum after the collision or interaction.

2. Why is conservation of momentum important?

Conservation of momentum is important because it helps us understand and predict the motion of objects in a system. It also allows us to analyze and explain various phenomena, such as collisions and explosions.

3. How is conservation of momentum related to Newton's laws of motion?

Conservation of momentum is related to Newton's laws of motion through the law of conservation of momentum, which is a direct consequence of Newton's third law. This law states that for every action, there is an equal and opposite reaction.

4. Can the conservation of momentum be violated?

No, the conservation of momentum is a universal law and cannot be violated. It has been tested and proven to hold true in all known physical systems.

5. How does conservation of momentum apply in real-world situations?

Conservation of momentum applies in various real-world situations, such as collisions between objects, rocket propulsion, and even sports, such as billiards and ice skating. It also plays a crucial role in the functioning of machines, such as cars and airplanes.

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