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chestycougth
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I am trying to revise this subject but I am unsure which of the two method's I've used is the correct one. Can someone help me?
two trucks travel towards each other. truck A has a velocity of 10 m/s and truck B has a velocity of 3 m/s. Truck A has a mass of 1000 kg and truck B has a mss of 1500 kg. Find the velocity of B after the collision if A has a velocity of 1 m/s afterwards in the same direction has before the collision.
2. relevant equations
total momentum before collision = total momentum after collision
p = mv
method 1
total momentum = (1000 * 10) + (1500 * 3) = 14500 kg m/s
momentum of A after collision = 1000 * 1 = 1000 kg m/s
momentum of B after collision = 14500 - 1000 = 13500 kg m/s
velocity of B:
v = p/m
v = 13500 / 1500 = 9 m/s
method 2
1 = (1000 * 10) - 1500v
1500v = 1000 * 10
v = 1000 *10 / 1500 = 6.6 m/s
Thanks.
Homework Statement
two trucks travel towards each other. truck A has a velocity of 10 m/s and truck B has a velocity of 3 m/s. Truck A has a mass of 1000 kg and truck B has a mss of 1500 kg. Find the velocity of B after the collision if A has a velocity of 1 m/s afterwards in the same direction has before the collision.
2. relevant equations
total momentum before collision = total momentum after collision
p = mv
The Attempt at a Solution
method 1
total momentum = (1000 * 10) + (1500 * 3) = 14500 kg m/s
momentum of A after collision = 1000 * 1 = 1000 kg m/s
momentum of B after collision = 14500 - 1000 = 13500 kg m/s
velocity of B:
v = p/m
v = 13500 / 1500 = 9 m/s
method 2
1 = (1000 * 10) - 1500v
1500v = 1000 * 10
v = 1000 *10 / 1500 = 6.6 m/s
Thanks.