- #1
needhelp83
- 199
- 0
The takeoff speed of a jetliner is 360 km/h. If the jetliner is to take off from a 2100 m long runway, what must be the (constant) acceleration along the runway?
Velocity of jetliner=(360 km/h)(1000 m/ 1 km)(1 h/3600 s)=100 m/s
v^2=initial V^2+2a(x-initial x)
(v^2-(initial V^2))/(x-intial x)=2a
((100 m/s)^2-0)/(2100-0)=2a
4.76 m/s^2=2a
a=2.38 m/s^2
Look right?
Anybody?
Velocity of jetliner=(360 km/h)(1000 m/ 1 km)(1 h/3600 s)=100 m/s
v^2=initial V^2+2a(x-initial x)
(v^2-(initial V^2))/(x-intial x)=2a
((100 m/s)^2-0)/(2100-0)=2a
4.76 m/s^2=2a
a=2.38 m/s^2
Look right?
Anybody?
Last edited: