- #1
Fek
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Homework Statement
- Rocket is accelerating constantly. Let S' be instantaneous rest frame of rocket and S be frame in which rocket is observed moving at velocity v.
Homework Equations
Given: $$ dv = dv' (1 - v^2) $$
Must prove:
$$ \frac{dv}{dt} = \frac{dv'}{dt'} (1 - v^2)^{\frac{3}{2}} $$
The Attempt at a Solution
So differentiate given equation with respect to t and use chain rule to get in terms of t'
$$ \frac{dv}{dt} = \frac{dt'}{dt} * \frac{d}{dt'}[dv'(1 - v^2)] $$
We also know
$$ \frac{dt'}{dt} = (1 - v^2)^{\frac{1}{2}} $$
as t' is proper time.
We also have:
$$ \frac{d}{dt'} (dv' (1 - v^2) = \frac{dv'}{dt'} (1 - v^2) $$
We have the answer! Except this final step isn't right because v is a function of t' as well and chain rule must be used?