Constantly accelerating rocket algebra problem

In summary, the given equation of dv = dv'(1 - v^2) must be differentiated with respect to t and using the chain rule to get it in terms of t'. The equation of dt'/dt = (1 - v^2)^{1/2} is also known as t' is proper time. However, the final step of differentiating dv'(1 - v^2) is not correct as v is a function of t' and chain rule must be used instead.
  • #1
Fek
16
0

Homework Statement


  • Rocket is accelerating constantly. Let S' be instantaneous rest frame of rocket and S be frame in which rocket is observed moving at velocity v.

Homework Equations


Given: $$ dv = dv' (1 - v^2) $$

Must prove:
$$ \frac{dv}{dt} = \frac{dv'}{dt'} (1 - v^2)^{\frac{3}{2}} $$

The Attempt at a Solution



So differentiate given equation with respect to t and use chain rule to get in terms of t'

$$ \frac{dv}{dt} = \frac{dt'}{dt} * \frac{d}{dt'}[dv'(1 - v^2)] $$
We also know
$$ \frac{dt'}{dt} = (1 - v^2)^{\frac{1}{2}} $$
as t' is proper time.

We also have:
$$ \frac{d}{dt'} (dv' (1 - v^2) = \frac{dv'}{dt'} (1 - v^2) $$

We have the answer! Except this final step isn't right because v is a function of t' as well and chain rule must be used?
 
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  • #2
If you have a functional equation, you can differentiate it. If you have an equation involving infinitesimal differentials, you can't differentiate it. Instead, you can divide by another infinitesimal differential.
 

Related to Constantly accelerating rocket algebra problem

1. How is acceleration calculated in a rocket launch?

Acceleration in a rocket launch is calculated by dividing the change in velocity by the change in time. This is the same as the slope of the velocity-time graph.

2. Why is constant acceleration important in rocket launches?

Constant acceleration is important in rocket launches because it allows the rocket to reach higher speeds and escape Earth's gravitational pull. It also ensures a smooth and controlled flight path.

3. How is the velocity of a rocket affected by the acceleration?

The velocity of a rocket is directly affected by the acceleration. As the acceleration increases, the velocity also increases at a constant rate.

4. Can you use algebra to solve rocket acceleration problems?

Yes, algebra can be used to solve rocket acceleration problems. By using equations such as v = u + at and s = ut + 0.5at^2, we can calculate the acceleration, initial velocity, final velocity, and displacement of a rocket at any given time.

5. How can we calculate the maximum height reached by a rocket using acceleration?

The maximum height reached by a rocket can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement. By setting the final velocity to 0, we can solve for the maximum height reached by the rocket.

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