Constructing wave function for Beryllium (Z=4)

In summary, the conversation discusses using an independent particle approximation to construct the wave functions for the ground and excited states of the Beryllium atom, taking into account the Pauli exclusion principle. The singlet and triplet states are also mentioned, with the singlet state having paired spins and the triplet state having unpaired spins. The conversation also touches on extending this concept to a 4 electron system and the importance of considering the Pauli exclusion principle in choosing the relevant spin functions.
  • #1
adwodon
13
0

Homework Statement



Using an independent particle approximation to construct the wave functions of the ground and the first singlet and triplet excited states of the Beryllium atom in terms of the hydrogen-like atomic orbitals, which satisfy the Pauli Exclusion Principle.

Homework Equations



n/a

The Attempt at a Solution



Ok so it's been a while since I've done any molecular physics so I'm getting a bit stumped at the basics and need a bit of pointing in the right direction.

So the ground state will be

1s2 2s2 right?
With spins like this:

2s [itex]\uparrow[/itex] [itex]\downarrow[/itex]
1s [itex]\uparrow[/itex] [itex]\downarrow[/itex]

1s2 2s 2p would be the first excited state?

2p [itex]\uparrow[/itex] or [itex]\downarrow[/itex]
2s [itex]\uparrow[/itex] or [itex]\downarrow[/itex]
1s [itex]\uparrow[/itex] [itex]\downarrow[/itex]

Is this the triplet state? ie you can have 3 different orientations of the spins, both up, both down, or a mix as there are 2 unpaired electrons?

Would the singlet state be 1s2 2p2? As the electrons are paired?

Ok so from there I have to construct the wave functions, is this a case of summing the products of spatial and spin functions or is it simpler than that?

I get that for a two electron system the spin functions are:

[itex]\frac{1}{\sqrt{2}}[/itex][[itex]\alpha[/itex](1)[itex]\beta[/itex](2)-[itex]\alpha[/itex](1)[itex]\beta[/itex](2)] - singlet

[itex]\alpha[/itex](1)[itex]\alpha[/itex](2) - triplet

[itex]\frac{1}{\sqrt{2}}[/itex][[itex]\alpha[/itex](1)[itex]\beta[/itex](2)+[itex]\beta[/itex](1)[itex]\alpha[/itex](2)] -triplet

[itex]\beta[/itex](1)[itex]\beta[/itex](2) - triplet

How do you extend this to a 4 electron system, and will all spin functions be relevant?

Obviously you'd have

[itex]\alpha[/itex](1)[itex]\alpha[/itex](2)[itex]\alpha[/itex](3)[itex]\alpha[/itex](4)
[itex]\beta[/itex](1)[itex]\beta[/itex](2)[itex]\beta[/itex](3)[itex]\beta[/itex](4)

Im guessing the rest would be combinations of α & β, are there any specifics I should watch out for?

Then spatial wavefunctions would just be of the form:

u[itex]_{nlm}[/itex](r) = R[itex]_{nl}[/itex](r)Y[itex]_{lm}[/itex]([itex]\vartheta[/itex],[itex]\varphi[/itex])

And I just pair the relevant spin functions with their spatial functions to get the wavefunctions I want.

Any help would be appreciated.
 
Physics news on Phys.org
  • #2


Hello,

It seems like you have a good understanding of the basic concepts involved in constructing the wave functions for the Beryllium atom. To answer your question about the singlet and triplet states, you are correct in thinking that the singlet state would have paired spins, while the triplet state would have unpaired spins.

To extend this to a 4 electron system, you would need to consider all possible combinations of α and β electrons, just as you did for the 2 electron system. However, in this case, you would have to take into account the Pauli exclusion principle, which states that no two identical fermions (such as electrons) can occupy the same quantum state simultaneously. This means that certain combinations of α and β electrons will not be allowed, so you will have to be careful in choosing the relevant spin functions for each spatial wavefunction.

Overall, you are on the right track with your approach. Just remember to consider the Pauli exclusion principle and make sure that your spin functions are consistent with the number of electrons in the system. Good luck with your calculations!
 

Related to Constructing wave function for Beryllium (Z=4)

1. How do you construct a wave function for Beryllium?

To construct a wave function for Beryllium, you first need to determine the number of electrons in the atom (Z=4). Then, you can use the Schrödinger equation and the principles of quantum mechanics to calculate the energy levels and probabilities of finding each electron in a specific location around the nucleus.

2. What factors influence the construction of a wave function for Beryllium?

The main factors that influence the construction of a wave function for Beryllium include the number of electrons, the nuclear charge (Z=4), the principle quantum number (n), the azimuthal quantum number (l), and the magnetic quantum number (m).

3. How does the construction of a wave function for Beryllium differ from other elements?

The construction of a wave function for Beryllium is similar to other elements in that it follows the principles of quantum mechanics. However, the number of electrons and the nuclear charge (Z=4) are unique to Beryllium and therefore, the specific values used in the Schrödinger equation will be different.

4. Can you construct a wave function for Beryllium without using the Schrödinger equation?

No, the Schrödinger equation is the fundamental equation used to calculate wave functions for atoms. It takes into account the properties of the electron, such as its mass and charge, and the forces acting on it from the nucleus. Without using this equation, it would be impossible to accurately construct a wave function for Beryllium.

5. What is the significance of constructing a wave function for Beryllium?

Constructing a wave function for Beryllium allows us to understand the behavior and properties of the atom, such as its energy levels and the probabilities of finding electrons in different locations. This information is crucial for understanding chemical bonding, reactions, and other physical properties of Beryllium and its compounds.

Similar threads

  • Advanced Physics Homework Help
Replies
2
Views
357
  • Quantum Physics
Replies
24
Views
843
  • Advanced Physics Homework Help
Replies
3
Views
2K
  • Quantum Physics
Replies
7
Views
1K
  • Advanced Physics Homework Help
Replies
3
Views
959
Replies
1
Views
724
Replies
8
Views
841
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
1K
Back
Top