- #1
TheDonk
- 67
- 0
Assume I am holding a bar parallel to the ground. I let go of the bar and it lands on something at an arbitrary point on the bar before it hits the ground. How much force is dealt to the object (and bar)?
This is the problem, but I'm going to simplify it to make a calculation possible. First imagine the situation in two dimensions. A bar falling and landing on a small circle with no air resistance. Also let's not bother with gravity and just say that the velocity is perpenticular to the bar (downwards) at contact.
I think the major factor to calculate this force is the composition of the bar and triangle. So assume that the objects are completely solid, with absolutely no compression. The bar has uniform density.
Bar's length = L
Bar's width = W
Bar's mass = M
Bar's center point = C = (Cx, Cy)
Bar's contact point = H = (Hx, Hy)
So if you know an equation for the contact force or I haven't given enough information to come to an exact answer, please reply.
This is the problem, but I'm going to simplify it to make a calculation possible. First imagine the situation in two dimensions. A bar falling and landing on a small circle with no air resistance. Also let's not bother with gravity and just say that the velocity is perpenticular to the bar (downwards) at contact.
I think the major factor to calculate this force is the composition of the bar and triangle. So assume that the objects are completely solid, with absolutely no compression. The bar has uniform density.
Bar's length = L
Bar's width = W
Bar's mass = M
Bar's center point = C = (Cx, Cy)
Bar's contact point = H = (Hx, Hy)
So if you know an equation for the contact force or I haven't given enough information to come to an exact answer, please reply.