- #1
fraggle
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Homework Statement
Suppose f:X-->Y
suppose for each open set U in Y s.t U contains some element f(x), we have f^(-1)(U) is open in X.
Does this imply f is continuous
Homework Equations
U is not quite an arbitrary open set of Y since there could be an open set of Y that does not interesct the image f(X).
Suppose V is such a set.
Then can we say f^(-1)(V)= the empty set? Or is it just undefined?
This isn't a homework question, just curious.
The Attempt at a Solution
I believe it is continuous since, otherwise the proof I'm reading in a textbook wouldn't work (they just ommited this part).
Could anyone explain the reasoning for this?
thank you