Contour map and Intersection points

In summary, the conversation includes drawing a contour map for a given function, finding the direction of maximum increase in height at a given point, and finding the point closest to the origin on the curve of intersection of a plane and a cone. The homework equations involve setting the function equal to different constants and calculating using the Lagrange multiplier method. The final solution involves finding the intersection points and determining which one is closest to the origin.
  • #1
Arcon
1
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Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 
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  • #2
Arcon said:

Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)
Do you understand what a "contour map" IS? No, don't set h(x,y)= z. A contour map of a function of two variables is a graph is the xy-coordinates system. Set h(x,y)= equal to a number of different constants and graph each of them. (Looks to me like you will have a number of different hyperbolas with the same asymptotes.)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h
Okay, that's the "Lagrange multiplier" method.

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 

FAQ: Contour map and Intersection points

What is a contour map?

A contour map is a type of map that represents the elevation of a geographic area through a series of contour lines. These lines connect points of equal elevation, allowing viewers to visualize the shape and steepness of the land.

How are contour maps created?

Contour maps are created by using data collected from various methods, such as aerial photography, LiDAR, or satellite imagery. This data is then processed and analyzed to determine the elevation of the land, which is then represented as contour lines on the map.

What are intersection points on a contour map?

Intersection points on a contour map are points where two or more contour lines intersect. These points indicate a change in elevation and can be used to identify the highest and lowest points on the map.

How are intersection points used in contour maps?

Intersection points are useful in contour maps for identifying land features such as hills, valleys, and ridges. They can also be used to determine the gradient or slope of the land at a specific location.

Can contour maps be used for navigation?

While contour maps are primarily used for visualizing elevation, they can also be used for navigation purposes. With the help of a legend and scale, you can estimate the distance and difficulty of a particular route, making contour maps useful for hikers and outdoor enthusiasts.

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