- #1
amrice
- 1
- 0
Hello, I'm have just started on this subject, and I am confused with the following equation:
since E(t) = kq(t)
=> [tex]\frac{dE}{dt}[/tex] = k [tex]\frac{dq}{dt}[/tex] = k*I
=> E = [tex]\int(kIdt)[/tex]
so if there is a constant current, wouldn't my electric field blow up??
Thanks!
since E(t) = kq(t)
=> [tex]\frac{dE}{dt}[/tex] = k [tex]\frac{dq}{dt}[/tex] = k*I
=> E = [tex]\int(kIdt)[/tex]
so if there is a constant current, wouldn't my electric field blow up??
Thanks!