- #1
chwala
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- TL;DR Summary
- I am going through the notes- refreshing. Would like to share my insight and probably clear some doubts highlighted in purple below.
Theorem
1. If a series ##{a_n}## converges, then the sequence ##{a_n}## converges to ##0##.
Now, the contra does not apply, and my question is why? i.e if the the sequence ##{a_n}## converges to ##0## then the series may or may not converge correct? and if it does not converge to ##0## then it diverges i.e for e.g ## \sum_{n=1}^\infty \dfrac{1}{2n}##
##\lim_{n→∞} \dfrac{1}{2n}=0## but the series diverges.
Secondly, in establishing convergence of series- we can look at a series on the context of a function i.e for e.g we can look at
## {a_n}=\sum_{n=1}^\infty \dfrac{1}{2n}## as ##f(x) = \sum_{x=1}^\infty \dfrac{1}{2x}##.
Thirdly, it seems to me that the the integral test is the more general approach to use in establishing on whether or not a series converges or diverges? other than the other available tests i.e ratio, comparison, p-test. Correct?
1. If a series ##{a_n}## converges, then the sequence ##{a_n}## converges to ##0##.
Now, the contra does not apply, and my question is why? i.e if the the sequence ##{a_n}## converges to ##0## then the series may or may not converge correct? and if it does not converge to ##0## then it diverges i.e for e.g ## \sum_{n=1}^\infty \dfrac{1}{2n}##
##\lim_{n→∞} \dfrac{1}{2n}=0## but the series diverges.
Secondly, in establishing convergence of series- we can look at a series on the context of a function i.e for e.g we can look at
## {a_n}=\sum_{n=1}^\infty \dfrac{1}{2n}## as ##f(x) = \sum_{x=1}^\infty \dfrac{1}{2x}##.
Thirdly, it seems to me that the the integral test is the more general approach to use in establishing on whether or not a series converges or diverges? other than the other available tests i.e ratio, comparison, p-test. Correct?
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