Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n)

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In summary, we are trying to show that the series \sum|x_n-x_{n+1}| converges, given that (a_n) and (b_n) are bounded decreasing and increasing sequences respectively, and x_n = a_n + b_n. We attempted to use the triangle inequality to simplify the series, but found that it does not work due to insufficient information. However, we can remove the absolute value signs and use the fact that bounded monotonic sequences are convergent to show that the terms of the series go to 0, and therefore it converges. By showing that the right hand side converges to a finite value, we can conclude that the left hand side, which has positive terms and is bounded above,
  • #1
Treadstone 71
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"Let (a_n) be bounded decreasing and (b_n) be bounded increasing sequences. Let x_n =a_n+b_n. Show that [tex]\sum|x_n-x_{n+1}|[/tex] converges."

This ALMOST is a telescoping sum, but it doesn't work since if I try to use the triangle inequality, the sum I want is on the greater side. Ratio test, root test, etc all fail since there is insufficient information.
 
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  • #2
How did you try to apply the triangle inequality? Try different groupings of the terms.
 
  • #3
By the triangle inequality,

[tex]\sum|x_n-x_{n+1}| = \sum|a_n+b_n-(a_{n+1}+b_{n+1})| \leq \sum|a_n-a_{n+1}|+\sum|b_n-b_{n+1}|[/tex]​

also, bounded monotonic sequences are convergent.
 
  • #4
They are indeed convergent, but showing that the terms of the series go to 0 is insufficient to show that it converges. If we remove the absolute value signs, it becomes a telescoping sum and therefore it converges. Knowing that, and that an, bn converge, can we conclude something from it?
 
  • #5
Treadstone 71 said:
They are indeed convergent, but showing that the terms of the series go to 0 is insufficient to show that it converges. If we remove the absolute value signs, it becomes a telescoping sum and therefore it converges. Knowing that, and that an, bn converge, can we conclude something from it?

Yes, you will have shown the right hand side converges to a finite value. The left hand side has positive terms and is then bounded above, so?
 
  • #6
How did you conclude that the RHS converges?
 
  • #7
Nevermind, I figured it out, thanks.
 

FAQ: Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n)

What is a Convergent Telescoping Sum?

A Convergent Telescoping Sum is a type of infinite series where the terms of the sum "telescope" or cancel each other out, resulting in a finite value when the series is added up.

What are Bounded Sequences (a_n) and (b_n)?

Bounded Sequences (a_n) and (b_n) are sequences of numbers where the values are all within a certain range or bound. This means that the terms of the sequences do not become infinitely large or small, but instead stay within a specific range.

How do you determine if a Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n) actually converges?

In order for a Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n) to converge, both sequences must be convergent and the limit of the ratio of the terms of the sequences must equal zero. This means that the values of the sequences must approach a finite value as n approaches infinity.

Can a Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n) diverge?

Yes, a Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n) can diverge if either of the sequences is divergent or if the limit of the ratio of the terms is not equal to zero. In this case, the sum will not approach a finite value and will instead approach infinity.

How can Convergent Telescoping Sums with Bounded Sequences (a_n) and (b_n) be used in real-life applications?

Convergent Telescoping Sums with Bounded Sequences (a_n) and (b_n) can be used to approximate the values of infinite series in mathematics and in various real-world scenarios, such as in finance and physics. They can also be used to model population growth and decay, as well as in the analysis of algorithms and computer programs.

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