Convert 55lb-65lb Draw Weight to 1/2kx^2

In summary, to convert the draw weight of 55lbs-65lbs into a value that can be used in the equation 1/2kx^2, you can use pounds-of-force directly and use feet for x, with the coefficient k being in pounds/foot. Keep in mind that this will give you the energy in foot-pounds. If you want to get the energy in Joules, you should use meters for x and convert pounds-of-force to Newtons (1 pound = 4.445 Newtons). Another method to find the value is by using the velocity of the arrow.
  • #1
logaliciouz
12
0
I'm Canadian, and I'm trying to convert the draw weight (55lb-65lb) into something I can put into 1/2kx^2. Please help!
 
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  • #2
You can use pounds-of-force directly and using feet for x, so long as you are happy with coefficient k being in pounds/foot, which are standard imperial units for spring coefficient.

Keep in mind that you'll get energy in foot-pounds. If you want to get energy in Joules, you should use meters for x and convert pounds-of-force to Newtons. There are 4.445 Newtons to a pound.
 
  • #3
okay thanks, I actually tried using a different method of finding it, using the velocity of the arrow, and it ended up working
 

FAQ: Convert 55lb-65lb Draw Weight to 1/2kx^2

What is "Convert 55lb-65lb Draw Weight to 1/2kx^2"?

"Convert 55lb-65lb Draw Weight to 1/2kx^2" is a formula used in physics to calculate the potential energy of a bow with a draw weight ranging from 55 to 65 pounds.

Why is this conversion important?

This conversion is important because it allows us to determine the amount of potential energy stored in a bow, which is necessary for understanding its performance and effectiveness.

How do I convert draw weight to potential energy?

To convert draw weight to potential energy using this formula, you first need to determine the draw weight of the bow in pounds. Then, you can plug that value into the formula along with the constant for gravitational acceleration (1/2) and the draw distance (x) in meters squared.

Can this formula be used for any type of bow?

Yes, this formula can be used for any type of bow as long as the draw weight is between 55 and 65 pounds and the draw distance is measured in meters.

Are there any limitations to this conversion?

This conversion is based on certain assumptions and may not be completely accurate in real-world scenarios. Factors such as friction, air resistance, and variations in bow design can affect the final potential energy calculation.

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