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EnglshGentlem
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I am fairly certain I am doing it right, but I want to double check.
"If you have a 25 denier string, what is its weight in pound-force per mile?"
These aren't so much as equations, but conversions.
1 Denier = 1g per 9000m
1g = 0.0098066 N
1 N = .2248 lb(f)
1 mile = 1609.344 m
So there are 25 denier, so that means there are 25 g per 9000m. I want it to be in pound force, so I can just convert grams into Newtons, and then Newtons in pound-force, right?
So .025*9.0866 = .24515 Newtons. Do another conversion, and that is .05512 lb(f)
So now we have that there are .05512 lb(f) per 9000m.
There are 5.592 miles in 9000m, so that should just be (.05512/5.592) to give me:
.009857 lb(f)/mile
Homework Statement
"If you have a 25 denier string, what is its weight in pound-force per mile?"
These aren't so much as equations, but conversions.
Homework Equations
1 Denier = 1g per 9000m
1g = 0.0098066 N
1 N = .2248 lb(f)
1 mile = 1609.344 m
The Attempt at a Solution
So there are 25 denier, so that means there are 25 g per 9000m. I want it to be in pound force, so I can just convert grams into Newtons, and then Newtons in pound-force, right?
So .025*9.0866 = .24515 Newtons. Do another conversion, and that is .05512 lb(f)
So now we have that there are .05512 lb(f) per 9000m.
There are 5.592 miles in 9000m, so that should just be (.05512/5.592) to give me:
.009857 lb(f)/mile