Converting a Third-Order Differential Equation into a Vector System?

In summary, To convert the differential equation for x into a system of first order differential equations, we can use the substitution y = x' and z = y' to get a system of equations in the form x' = y, y' = z, and z' = -2z^2. Using the standard notation for derivatives, we can rewrite this as the vector form x' = y, y' = z, and z' = -2z^2.
  • #1
johnaphun
14
0

Homework Statement



Convert the differential equation for x,

x''' + 2(x''2) = 0

Into a system of first order differential equations. Put the system in vector form

Homework Equations





The Attempt at a Solution



I'm able to do this for simpler DE's but I can't seem to find an answer for this one. Do i need to do anything different because of the 3rd derivative?
 
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  • #2
hi johnaphun! :smile:

what's the difficulty? :confused:

put a = x'' and solve, then put v = x' and solve
 
  • #3
Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Since your equation is [itex]x'''+ 2(x'')^2= 0[/itex], let y= x' and z= y'= x'' so that x'''= z'. Now, [itex]x'''+ 2(x'')^2= z'+ 2z^2= 0[/itex], [itex]y'= z[/itex], and [itex]x'= y[/itex].
 
  • #4
HallsofIvy said:
Same thing except that I tend to prefer to use letters near the beginning of the alphabet, like "a", to represent constants, letters near the end, like "x", to represent variables.

Normally, I'd agree! :smile: … but this equation looked to me like a dynamical equation, with x being distance, so I preferred the familiar form of x' = v, v' = a. :wink:
 

FAQ: Converting a Third-Order Differential Equation into a Vector System?

What is a linear dynamical system?

A linear dynamical system is a mathematical model used to describe the evolution of a system over time. It consists of a set of variables and a set of equations that govern the relationships between these variables. The system is said to be linear if the equations are linear, meaning that the variables appear only to the first power and there are no cross-terms.

What are the applications of linear dynamical systems?

Linear dynamical systems have a wide range of applications in various fields such as physics, engineering, economics, and biology. They are commonly used to model and analyze the behavior of systems in which the relationships between variables are linear, such as in mechanical and electrical systems, population dynamics, and economic systems.

How do you solve a linear dynamical system?

The solution to a linear dynamical system can be obtained by using various methods such as analytical, numerical, and graphical techniques. In analytical methods, the system is solved using algebraic operations to find the values of the variables at different time points. Numerical methods use computer algorithms to approximate the solution, while graphical methods involve plotting the variables over time to visualize the system's behavior.

What are the stability properties of linear dynamical systems?

The stability of a linear dynamical system refers to the behavior of the system over time. A system is considered stable if its variables converge to a steady state or oscillate around a fixed point. The stability of a system is determined by the eigenvalues of the system's matrix. If all eigenvalues have negative real parts, the system is stable, while positive eigenvalues indicate instability.

How do nonlinearities affect linear dynamical systems?

Nonlinearities, such as higher-order terms and cross-terms, can significantly impact the behavior of linear dynamical systems. They can result in complex and unpredictable behavior, including chaos and bifurcations. Therefore, it is essential to consider nonlinearities in the modeling and analysis of linear dynamical systems to accurately describe their behavior.

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