Converting parsecs to Mega-parsecs

[Krissy0612]

I am doing a lab and it asks me to figure the distance of an object in pc (parsecs) and then it asks to figure the distance of the same object in Mpc (Mega-parsecs).

*I know that D= 10^((m-M+5)/5) <---will this get me Distance in pc?
If it does than I think I did this right.
D= 10^((14.62- -22+5)/5)= 10^(41.62/5)= 10^8.324

Now I just need to know how to convert parsecs into Mpc. My teacher has not gone over this in class.

Can anyone help me? If so, it'd be greatly appreciated! Thank you!

 

[selfAdjoint]

I am doing a lab and it asks me to figure the distance of an object in pc (parsecs) and then it asks to figure the distance of the same object in Mpc (Mega-parsecs).

*I know that D= 10^((m-M+5)/5) <---will this get me Distance in pc?
If it does than I think I did this right.
D= 10^((14.62- -22+5)/5)= 10^(41.62/5)= 10^8.324

Now I just need to know how to convert parsecs into Mpc. My teacher has not gone over this in class.

Can anyone help me? If so, it'd be greatly appreciated! Thank you!

Mega means a million. A megaparsec is a million parsecs. To get the number of megaparsecs divide the number od parsecs by a million.

 

[sir-pinski]

To convert parsecs (pc) to Mega-parsecs (Mpc), you can use the fact that 1 Mpc is equal to 1 million pc. So, to convert from pc to Mpc, you simply need to divide the distance in pc by 1 million. In your case, the distance in Mpc would be 10^8.324 / 1 million = 0.00001 Mpc. So the distance of the object is approximately 0.00001 Mpc or 10 pc.

It seems like you have correctly calculated the distance in pc using the formula D= 10^((m-M+5)/5). Just remember to always double check your units and make sure they are consistent. In this case, the units for the distance in pc should be pc, and the units for the distance in Mpc should be Mpc.

I hope this helps and good luck with your lab!