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dlp248
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Homework Statement
The deepest part of the ocean is about 10,900 meters deep. Calculate the pressure at that depth in units of N/m^2. Mass density for seawater is 1030 kg/m^3. Then convert the pressure to the number of atmospheres given one atmosphere is 1.013x10^5 N/m^2.
Homework Equations
pressure = mass density x gravity x height
The Attempt at a Solution
p= (1030 kg/m^3)(9.8 m/s^2)(10,900 m)
p= 1.10x10^8 N/m^2
1 atmosphere = 1.013x10^5 N/m^2
1.10x10^8 N/m^2 / 1.013x10^5 N/m^2 = 1086 atmospheres.
I know that number is wrong. My guess is there are about 1.3 - 1.4 atmospheres of pressure there, but I can't get the math to find an exact number for that conversion. What is the best way to convert pressure to atmospheres?