- #1
Raerin
- 46
- 0
So how do I convert r=4+4cos(theta) into rectangular form?
I know that r^2 = x^2+y^2 and that rcos(theta) = x.
Would the start of the solution be:
sqrt(x^2 + y^2) = 4+4x
If yes, I don't know where to go from there.
I know that r^2 = x^2+y^2 and that rcos(theta) = x.
Would the start of the solution be:
sqrt(x^2 + y^2) = 4+4x
If yes, I don't know where to go from there.