- #1
batcave1985
- 7
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Shiny lawn spheres placed on pedestals are convex mirrors.
One such sphere has a diameter of 40 cm. A
12 cm long robin sits in a tree 1.5 m from the sphere.
(a) Where is the image of the robin?
(b) How long is the image?
f=R/2 to find radius
1/v=1/f-1/u to find image distance (the mirror equation)
M=v/u magnification and length (maginification equation)
my answer just not to sure if its right.
a)
f=r/2
=20/2
f=10cm
u=150cm
1/v=-1/1-1/50
v= -9.4cm
b) m=v/u
= -9.4/150
= 0.06cm
not to sure if that was the way to go.
One such sphere has a diameter of 40 cm. A
12 cm long robin sits in a tree 1.5 m from the sphere.
(a) Where is the image of the robin?
(b) How long is the image?
f=R/2 to find radius
1/v=1/f-1/u to find image distance (the mirror equation)
M=v/u magnification and length (maginification equation)
my answer just not to sure if its right.
a)
f=r/2
=20/2
f=10cm
u=150cm
1/v=-1/1-1/50
v= -9.4cm
b) m=v/u
= -9.4/150
= 0.06cm
not to sure if that was the way to go.