- #1
Lindsayyyy
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Hi everyone, I want to calculate the convolution of two triangluar pulses
both functions are given by
[tex] x(t)=\left\{\begin{array}{ll} t+1, & -1 \leq t \leq 0 \\
1-t, & 0 \leq t \leq 1 \end{array}\right. [/tex]
and I rewrote the other as h(-t+t)
convolution integral
So first of all I mirrored my function h(-tau) and then added +t so I have h(-tau+t)
Whenthe front (right) side of my h(-tau+t) is smaller than -1 I have no overlap [1+t<-1] so my integral is zero.
Now I'm not sure about the 2nd part. I think the second part is the following:
when the front of my h(-tau+t) is bigger than -1 but smaller than zero, then these conditions lead to:
1+t>-1 and 1+t<0 so my integration limits are from -1 to 1+t is that correct?
Thanks for your help in advance
Regards Lindsay
Homework Statement
both functions are given by
[tex] x(t)=\left\{\begin{array}{ll} t+1, & -1 \leq t \leq 0 \\
1-t, & 0 \leq t \leq 1 \end{array}\right. [/tex]
and I rewrote the other as h(-t+t)
Homework Equations
convolution integral
The Attempt at a Solution
So first of all I mirrored my function h(-tau) and then added +t so I have h(-tau+t)
Whenthe front (right) side of my h(-tau+t) is smaller than -1 I have no overlap [1+t<-1] so my integral is zero.
Now I'm not sure about the 2nd part. I think the second part is the following:
when the front of my h(-tau+t) is bigger than -1 but smaller than zero, then these conditions lead to:
1+t>-1 and 1+t<0 so my integration limits are from -1 to 1+t is that correct?
Thanks for your help in advance
Regards Lindsay