- #1
Stacyg
- 25
- 0
When a liquid is cooled, the difference between the temperature of the liquid and the surrondings is measured. The results are:
t(min) 10 20 30 40
T(°C) 60.7 36.8 22.3 13.5
Where t= time from the start of the cooling
T= temperature difference
Q(i) Process the above data and show that the cooling curve has the form:
T=Ae^(-kt)
I'm not sure how to do this. I have gone through the textbook and there are no similar questions to this. The only one close has a different form.
I tried getting a value for A using a computer programme, but it said that there is no algebraic solution. I also tried getting a value for -k that worked but I'm not sure how to transform this data to show a cooling curve.
b) Find the values of A and k.
Thanks for any help.
t(min) 10 20 30 40
T(°C) 60.7 36.8 22.3 13.5
Where t= time from the start of the cooling
T= temperature difference
Q(i) Process the above data and show that the cooling curve has the form:
T=Ae^(-kt)
I'm not sure how to do this. I have gone through the textbook and there are no similar questions to this. The only one close has a different form.
I tried getting a value for A using a computer programme, but it said that there is no algebraic solution. I also tried getting a value for -k that worked but I'm not sure how to transform this data to show a cooling curve.
b) Find the values of A and k.
Thanks for any help.