Coriolis acceleration at the surface of a region in the ocean

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Coriolis acceleration is being analyzed in a circular motion scenario at the ocean's surface, with a focus on a region centered at 30 degrees N. The velocity from point A to B is 0.5 m/s over a distance of 200 km. The formula for Coriolis acceleration, (2ωV sin latitude), is being applied to determine the acceleration vectors, which are expected to point to the right of each circular measurement. The challenge lies in sketching the magnitude of the Coriolis acceleration as a function of distance along the line from A to B, specifically from the center out to 100 km. A suggested approach includes plotting the magnitude against the distance from -100 to 100 km along the x-axis, with the y-axis representing the Coriolis acceleration values.
hamilbr
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Homework Statement



Hello everyone,
I am having some problems with a question about the coriolis acceleration in a particular region. Attached is an image showing velocity measurements going in a circular motion at the surface of the ocean. A to B is 200 km and the fastest velocity is .5 m/s. The center is located at 30 degrees N. I am asked to make vectors of coriolis acceleration at the small circles, which I am assuming would go to the right of each one. I am also asked to sketch the magnitude of the coriolis acceleration as a function of x along the line from A to B. X is the distance from the center of the figure along the line AB. It is also asked to sketch the x (eastward) and y (northward) component of the coriolis acceleration. I am really stumped on these last two things and any info would be greatly appreciated. Thanks
 

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welcome to pf!

hello hamilbr! welcome to pf! :smile:

i don't understand how far you've got, and where you're stuck :confused:

what equation are you using for the definition of Coriolis force?

what result does it give you for a typical point (x,y) in the diagram?
 
coriolis acceleration at the ocean surface

Hi Tiny-tim,

I am assuming I use (2 omega V sin latitude) for coriolis acceleration. I am just confused about sketching the magnitude of the acceleration as a function of x along the line from A to B where y=0. Would that mean that I start at the center and go out to 100 Km since that would be the radius? I am sure I am thinking too much and it is probably a fairly simple sketch. All the info I was given is in that first post so I feel like I am missing something.
 
hi hamilbr! :smile:
hamilbr said:
I am assuming I use (2 omega V sin latitude) for coriolis acceleration. I am just confused about sketching the magnitude of the acceleration as a function of x along the line from A to B where y=0. Would that mean that I start at the center and go out to 100 Km since that would be the radius?

let's see …

the velocity, V, from A to B is either due north or due south

so to get the graph of the magnitude of the coriolis acceleration from A to B, plot the value of 2ΩV|sinθ|, where θ is the angle between the Earth's axis and due north, along the y-axis, against distance from -100 to 100 along the x-axis :wink:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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