- #1
confused88
- 22
- 0
Can someone please correct my working out...
[tex] \frac{\beta^2}{(x-1)(x-2)} - \frac{\beta^2}{(x-1)^2}[/tex]
[tex]\frac{\beta^2(x-1)^2 - \beta^2(x-1)(x-2)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex]\frac{\beta^2x^2 - \beta^2 -\beta^2(x^2 - 3x +2)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex]\frac{3\beta^2 + 3\beta^2x}{(x-1)(x-2)(x-1)^2}[/tex]
[tex] \frac{3\beta^2(x -1)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex] \frac{3\beta^2}{(x-2)(x-1)^2}[/tex]
that's my answer..
but the real answer is meant to be:
[tex] \frac{\beta^2}{(x-2)(x-1)^2}[/tex]
Can someone see where i went wrong?
[tex] \frac{\beta^2}{(x-1)(x-2)} - \frac{\beta^2}{(x-1)^2}[/tex]
[tex]\frac{\beta^2(x-1)^2 - \beta^2(x-1)(x-2)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex]\frac{\beta^2x^2 - \beta^2 -\beta^2(x^2 - 3x +2)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex]\frac{3\beta^2 + 3\beta^2x}{(x-1)(x-2)(x-1)^2}[/tex]
[tex] \frac{3\beta^2(x -1)}{(x-1)(x-2)(x-1)^2}[/tex]
[tex] \frac{3\beta^2}{(x-2)(x-1)^2}[/tex]
that's my answer..
but the real answer is meant to be:
[tex] \frac{\beta^2}{(x-2)(x-1)^2}[/tex]
Can someone see where i went wrong?
Last edited: