- #1
Jeff57
- 2
- 0
I live in the country about 15 miles from the nearest power utility capacitor bank.
I believe this 15x2= 30 miles (round trip) of wire causes a reactive inductance (or internal resistance) by the time it reaches my home. I think this contributes to micro-brownouts or sags in the current available to me.
The previous owner had the yard littered with burn out frigs and electronics.
So large AC motors like air compressors with large stall amps, use starting capacitors during start up.
I decided to add my own 80 mfd 370vac Capacitors, one on each side of the 220 v mains at the meter panel.
The caps are from Packard Inc part # PRC80. My hope was that these would lower the "internal resistance" of my utility company, and stop any sagging of the leading edge of the sine wave.
Here's my issue, I connected one identical 80mfd cap to a power cord and plugged it into a "kill-a-watt" meter ( http://www.p3international.com/products/special/P4400/P4400-CE.html )
, which displays the power consumption of any device that is plugged into it.
What I found was confusing. My voltage was of course 121, but the Power Factor (PF) was 0.01, the amps was 3.7 , the watts read was 6 but the VA read 450.
So, am I paying a higher power bill because caps are drawing 6 watts 24/7 ?
Do these capacitors really correct my power factor and sag or am I wasting my time?
How can I show a 3.7 amp draw and the watts be only 6 and not 120vx3.7a ?
So I have florescent lights that indicate a P.F. of .55 using the same meter. I think I pay a penalty for phantom power draws less than 1.0 PF. So does the 0.01 of the cap, help or hurt me?
Not even the power company rep can give me a clear answer.
Thanks for the reply's. I would like to understand the math and how these things work.
-Jeff57 10/17/10
.
I believe this 15x2= 30 miles (round trip) of wire causes a reactive inductance (or internal resistance) by the time it reaches my home. I think this contributes to micro-brownouts or sags in the current available to me.
The previous owner had the yard littered with burn out frigs and electronics.
So large AC motors like air compressors with large stall amps, use starting capacitors during start up.
I decided to add my own 80 mfd 370vac Capacitors, one on each side of the 220 v mains at the meter panel.
The caps are from Packard Inc part # PRC80. My hope was that these would lower the "internal resistance" of my utility company, and stop any sagging of the leading edge of the sine wave.
Here's my issue, I connected one identical 80mfd cap to a power cord and plugged it into a "kill-a-watt" meter ( http://www.p3international.com/products/special/P4400/P4400-CE.html )
, which displays the power consumption of any device that is plugged into it.
What I found was confusing. My voltage was of course 121, but the Power Factor (PF) was 0.01, the amps was 3.7 , the watts read was 6 but the VA read 450.
So, am I paying a higher power bill because caps are drawing 6 watts 24/7 ?
Do these capacitors really correct my power factor and sag or am I wasting my time?
How can I show a 3.7 amp draw and the watts be only 6 and not 120vx3.7a ?
So I have florescent lights that indicate a P.F. of .55 using the same meter. I think I pay a penalty for phantom power draws less than 1.0 PF. So does the 0.01 of the cap, help or hurt me?
Not even the power company rep can give me a clear answer.
Thanks for the reply's. I would like to understand the math and how these things work.
-Jeff57 10/17/10
.