Cosmological gravitational waves

In summary, the exercise is to derive the form of the symmetric, trace-free and transverse gravitational wave perturbation ##\hat{E}_{ij}## to the FRW metric. The first step is to figure out the connection coefficients, which are supposed to be modified to account for the perturbation. After some calculations, including a correction of the metric on spatial slices to include the perturbation, it is found that the connection coefficients are equal to the Hubble parameter times the metric with the perturbation and the derivative of the perturbation. However, there are still some discrepancies in the equations which may be due to the series expansion used to find the inverse of the metric.
  • #1
etotheipi
The exercise is to derive the form of the symmetric, trace-free and transverse gravitational wave perturbation ##\hat{E}_{ij}## to the FRW metric$$ds^2 = a^2(\tau) \left[ -d\tau^2 + (\delta_{ij} + 2\hat{E}_{ij})dx^i dx^j \right]$$First step is to figure out the connection coefficients, which are supposed to be:

1622196030721.png

I presumed ##h_{ij}## is metric on the spatial slices i.e. ##h_{ij} = \delta_{ij} + 2\hat{E}_{ij}##, but that doesn't seem consistent with the above from what I worked out below. I reckon the notation ##\hat{E}_{ij}'## is supposed to be ##\partial_0 \hat{E}_{ij}##, but that I'm not totally sure about either. I'd worked out:\begin{align*}
\Gamma^0_{00} &= \frac{1}{2}g^{0m} \left( 2\partial_0 g_{m0} - \partial_m g_{00} \right) \\
&= \frac{1}{2} g^{00} \partial_0 g_{00} \\
&= \frac{1}{2} \cdot \frac{-1}{a^2} \cdot -2a \dot{a} = \frac{\dot{a}}{a} = \mathcal{H}

\\ \\

\Gamma^0_{ij} &= \frac{1}{2} g^{0m} \left( \partial_j g_{mi} + \partial_i g_{mj} - \partial_m g_{ij} \right) \\

&= \frac{1}{2} g^{00} \left( - \partial_0 g_{ij} \right) \\

&= \frac{-1}{2a^2} \left( -\partial_0 \left[a^2\left\{ \delta_{ij} + 2\hat{E}_{ij} \right\} \right] \right) \\

&= \frac{1}{2a^2} \left( 2a\dot{a} \left[ \delta_{ij} + 2\hat{E}_{ij} \right] + 2a^2 \hat{E}_{ij}' \right) \\

&= \mathcal{H} \left[ \delta_{ij} + 2\hat{E}_{ij} \right] + \hat{E}_{ij}'

\\ \\

\Gamma^i_{j0} &= \frac{1}{2} g^{im} \left( \partial_0 g_{mj} + \partial_j g_{m0} - \partial_m g_{j0} \right) \\

&= \frac{1}{2} g^{ik} \left( \partial_0 g_{kj} \right) \\

&= \frac{1}{2} g^{ik} \left( \partial_0 \left[ a^2 \left\{ \delta_{kj} + 2\hat{E}_{kj} \right\} \right] \right) \\

&= \frac{1}{2} g^{ik} \left( 2a \dot{a} \left[ \delta_{kj} + 2\hat{E}_{kj}\right] + 2a^2\hat{E}_{kj}' \right) \\

&= a^2 \mathcal{H} \left[ \delta^i_j + 2\hat{E}^i_j \right] + a^2{\hat{E}^{i}_j}' \\\\ \\

\Gamma^i_{jk} &= \frac{1}{2} g^{im}(\partial_k g_{mj} + \partial_j g_{mk} - \partial_m g_{jk}) \\

&= \frac{1}{2}g^{il} \left(\partial_k \left[ a^2 \left\{ \delta_{lj} + 2\hat{E}_{lj} \right\} \right] + \partial_j \left[ a^2 \left\{ \delta_{lk} + 2\hat{E}_{lk} \right\} \right] - \partial_l \left[ a^2 \left\{ \delta_{jk} + 2\hat{E}_{jk} \right\} \right]\right) \\

&= a^2 g^{il} \left(\partial_k \hat{E}_{lj} + \partial_j \hat{E}_{lk} - \partial_l \hat{E}_{jk} \right) \\

&= a^2 \left(\partial_k \hat{E}^i_{j} + \partial_j \hat{E}^i_{k} - g^{il} \partial_l \hat{E}_{jk} \right)

\end{align*}I don't really know what I'm doing wrong?
 
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  • #3
PeterDonis said:
From where?
You'd have thought after all this time I'd remember to post the link 😄
Seems old habits die hard...

It's question 4 here: https://www.damtp.cam.ac.uk/user/examples/3R2b.pdf
 
  • #4
I think I'm seeing a few places where the derivatives should have eliminated the ##\delta_{ij}## terms but did not (e.g., the second ##\delta_{ij}## terms in both the second and third equations).

As for ##h_{ij}##, I'm not sure. I'd recommend looking over this section in your textbook to see if the term is defined clearly, or just contacting your professor for the definition.
 
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  • #5
kimbyd said:
I think I'm seeing a few places where the derivatives should have eliminated the ##\delta_{ij}## terms but did not (e.g., the second ##\delta_{ij}## terms in both the second and third equations).
Oh golly, can't believe I missed that. I'll edit the post to correct them now and see if it's any closer. Thanks!
 
  • #6
etotheipi said:
I presumed ##h_{ij}## is metric on the spatial slices i.e. ##h_{ij} = \delta_{ij} + 2\hat{E}_{ij}##
Since this is about gravitational waves, the common notation for GWs is that ##h_{ij}## is the metric perturbation, which in this case would be ##2 E_{ij}##.

etotheipi said:
I reckon the notation ##\hat{E}_{ij}'## is supposed to be ##\partial_0 \hat{E}_{ij}##
That seems to be the only possibility, but I agree it's weird notation. A prime is normally used to denote a derivative with respect to a spatial coordinate, not time. But perhaps putting the hat on ##\hat{E}_{ij}## meant that putting a dot on top as well would have been cumbersome.
 
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  • #7
Hm, I think I've now corrected the mistakes that @kimbyd pointed out, but it's still not quite there. In particular I'm not sure why the last two still have ##a^2##s. Maybe I need to look at this again tomorrow 😄
 
  • #8
etotheipi said:
Hm, I think I've now corrected the mistakes that @kimbyd pointed out, but it's still not quite there. In particular I'm not sure why the last two still have ##a^2##s. Maybe I need to look at this again tomorrow 😄
I think for the very last term in the last equation, that might be from the metric (note that they have ##\delta^{il}## where you have ##g^{il}##), though I'm not understanding how they are making that substitution.

But that last equation confuses me in general. The asymmetry between the first two terms in the provided solution just seems wrong.
 
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  • #9
kimbyd said:
I think for the very last term in the last equation, that might be from the metric (note that they have ##\delta^{il}## where you have ##g^{il}##), though I'm not understanding how they are making that substitution.

But that last equation confuses me in general. The asymmetry between the first two terms in the provided solution just seems wrong.
Tentatively answering part of my own question:

The change from ##g^{il}## to ##\delta^{il}## may be down to using the series expansion for the inverse. It's not too hard to show that for a matrix ##A = I + B##, where ##I## is the identity and ##B## is small in the appropriate sense, ##A^{-1} = I - B + B^2 - B^3 + \dots##

They do mention that this is the answer to first order in ##\hat{E}##, after all.

But the first two terms in that last equation still confuse me. I don't see why they shouldn't be the same except with a couple of indices swapped. And I don't understand what's going on with the ##a^2##.
 
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  • #10
kimbyd said:
The change from ##g^{il}## to ##\delta^{il}## may be down to using the series expansion for the inverse. It's not too hard to show that for a matrix ##A = I + B##, where ##I## is the identity and ##B## is small in the appropriate sense, ##A^{-1} = I - B + B^2 - B^3 + \dots##

They do mention that this is the answer to first order in ##\hat{E}##, after all.
That makes sense, I didn't really know how to interpret the remark about working to first order in the ##\hat{E}_{ij}##. Maybe there are some further approximations that can be made. I must say it's very confusing 😄

There's a set of notes here: https://www.damtp.cam.ac.uk/user/examples/3R2La.pdf
but they aren't too helpful. The closest thing I could find was section 3.4 on linearised equations at the bottom of page 37, but they leave those as an exercise too.
 

FAQ: Cosmological gravitational waves

What are cosmological gravitational waves?

Cosmological gravitational waves are ripples in the fabric of space-time that are caused by the acceleration of massive objects, such as black holes or neutron stars. These waves were first predicted by Albert Einstein's theory of general relativity in 1916 and were recently observed for the first time in 2015.

How are cosmological gravitational waves detected?

Cosmological gravitational waves are detected using highly sensitive instruments called interferometers, which measure minute changes in the distance between two points caused by passing gravitational waves. Currently, the most advanced interferometers are the Laser Interferometer Gravitational-Wave Observatory (LIGO) and the Virgo interferometer.

What can we learn from studying cosmological gravitational waves?

Studying cosmological gravitational waves can provide us with valuable information about the origins and evolution of the universe. These waves can help us understand the behavior of matter and energy in extreme environments, such as near black holes, and can also provide evidence for the existence of cosmic events, such as the collision of two black holes.

Are there different types of cosmological gravitational waves?

Yes, there are two types of cosmological gravitational waves: primordial and astrophysical. Primordial gravitational waves are believed to have been created during the Big Bang and can provide insights into the early universe. Astrophysical gravitational waves are generated by the motion of massive objects in the present-day universe.

How do cosmological gravitational waves differ from electromagnetic waves?

Cosmological gravitational waves and electromagnetic waves are fundamentally different phenomena. Gravitational waves are disturbances in the fabric of space-time, while electromagnetic waves are oscillating electric and magnetic fields. Additionally, gravitational waves travel at the speed of light and can pass through any medium, while electromagnetic waves can be absorbed or scattered by matter.

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