Could someone check this for me? (photon and wavelength)

[confusedbyphysics]

This is a post-lab question for my chemistry lab. It's confusing because the questions are supposed to go along with what we are learning in the chemistry lecture, but we're behind in the lecture, so I'm trying to teach myself how to do this since we haven't learned it yet!
Here's the problem:

"The ionization energy of Li is 520 kJ/electron mole. What is the wavelength of nm of a photon having sufficient energy to remove an electron from Li? In what portion of the electromagnetic spectrum would you find such a photon?"

My work:

520 kJ = 520000 J

520000 J/mol X 1 mol / 6.02 X 10^23 photons = 8.6379 X 10^-19 J / photons

Energy = h (constant) X v (frequency)

v = E/h

v = (8.6379 X 10^-19 J/photons) / (6.626 X 10 ^-34 J/s)

v = 1.3036 X 10 15 /s

wavelength (w) = speed of light (c)/ v

w = (3 X 10^8 m/s) / (1.3036 X 10^15)

w = 2.301 m /photon X 10^9 nm/m = 230 nm

230 nm = ultraviolent rays
Does this look right? If someone could help me Id soooo appreciate it! (I need to make sure I did this right or I'll miss the next problem too because they're related)

 

[sanitykey]

All the steps and the results appear correct, i would of tackled this problem in exactly the same way.

 

[Blueshift5]

Hello,

Thank you for reaching out for assistance with this problem. First of all, it is great that you are taking the initiative to teach yourself the material ahead of the lectures. That shows a strong dedication to learning and understanding the concepts.

Now, onto the problem at hand. Your calculations and methods appear to be correct. You correctly used the equation E = hv and solved for the frequency (v). Then, you used the equation c = vλ to solve for the wavelength (λ). Your final answer of 230 nm is within a reasonable range for ultraviolet rays.

One thing to note is that the ionization energy of Li is typically given in units of kJ/mol, not kJ/electron mole. So, just be careful with the units when using the molar conversion factor in your calculations.

Overall, your approach and solution to this problem seem sound. Keep up the good work and don't hesitate to ask for help if you come across any other confusing problems. Good luck with the rest of your studies.