- #1
John Ker
- 16
- 1
Moved from a technical forum, so homework template missing.
A charge Q is placed at the centre of the square of side 2.90 cm, at the corners of which four identical charges q = 6.5 C are placed. Find the value of the charge Q so that the whole system is in equilibrium. Can someone help me figure out where I have went wrong, I began by finding the force on a single corner charge with the following calculations.
2 ( k *(6.5 * 6.5)/(.029^2)) + k(6.5*6.5)/(.04101)^2
(the .04101 is my diagonal distance calculated)
This gives me 1.31E15
Where I then go 1.31E15 = kqQ/r^2
Utilizing r = .04101/2
q = q
Q = 6.5
k = the constant
I get the incorrect answer of -8.124C
Any ideas?
2 ( k *(6.5 * 6.5)/(.029^2)) + k(6.5*6.5)/(.04101)^2
(the .04101 is my diagonal distance calculated)
This gives me 1.31E15
Where I then go 1.31E15 = kqQ/r^2
Utilizing r = .04101/2
q = q
Q = 6.5
k = the constant
I get the incorrect answer of -8.124C
Any ideas?