Coulomb's Law: Attraction/Repulsion & Approximate Force Calculation

In summary: Can you work out the answer?In summary, the two parallel dipoles shown repel each other. When considering the four charges as a rectangle, the charge at the upper-left is repelled by one of the charges on the right and attracted by another, while the charge at the lower-left experiences the same forces. Therefore, the net force is repulsive.
  • #1
kyrax
9
0

Homework Statement


Consider the two parallel electric dipoles shown.


+ (Q) + (Q) | (Distance=d/2)
------------------------------------------x------
- (-Q) - (-Q) | (Distance=d/2)
|-------Distance=X-----------|

a) Do the two dipoles attract or repel from each other
b) Let x>>d. Find an approximate expression for the force between the two dipoles. The expression is in terms of Q,d, and x.
C) sketch the graph of F vs. x.

Homework Equations


Coulombs's law
F=k(q1q2/r2

The Attempt at a Solution


I an completely new to Coulomb's law and dipoles so i don't know how to start.

a) The answer is they repel but i don't get why. I know the top/bottom two charges will repel but won't they attract each other diagonally?
b)Have not attempted. Don't know how to start.
c) Stuck on b. didnt get to this yet
 
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  • #2
I'm guessing your diagram was supposed to look like this?
Code:
   + (Q)                        + (Q)
   |                            |      (Distance=d/2)
 --x----------------------------x-----------
   |                            |      (Distance=d/2)
   - (-Q)                       - (-Q)
   |-------Distance=x-----------|

Forget about the fact that they're dipoles. Just think about it as a set of four charges at the corners of a rectangle, and figure out the force on each charge. You don't need the exact magnitude and direction (at least not for part a), but you can easily figure out whether there's more force acting to the left or the right on any particular charge.
 
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  • #3
diazona said:
I'm guessing your diagram was supposed to look like this?
Code:
   + (Q)                        + (Q)
   |                            |      (Distance=d/2)
 --x----------------------------x-----------
   |                            |      (Distance=d/2)
   - (-Q)                       - (-Q)
   |-------Distance=x-----------|

Forget about the fact that they're dipoles. Just think about it as a set of four charges at the corners of a rectangle, and figure out the force on each charge. You don't need the exact magnitude and direction (at least not for part a), but you can easily figure out whether there's more force acting to the left or the right on any particular charge.

yes, it should look like that. thanks.

i don't know how to find the forces.
would it be like this? assuming the Q's are: Q1(top left), Q2(top right), -Q3(bottom left), -Q4(bottom right)

FQ1=[k(Q1Q2)/x2]+[k(Q1-Q3)/d2]+[k(Q1-Q4)/(x2+d2)]?

and i do this for Q2, -Q3, -Q4?
 
  • #4
No equations needed for part a. Just think: the charge at the upper-left is repelled by one of the charges on the right and attracted by another. Which force is greater? Ditto for the charge at the lower-left.
 
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FAQ: Coulomb's Law: Attraction/Repulsion & Approximate Force Calculation

What is Coulomb's Law?

Coulomb's Law is a fundamental law of physics that describes the force of attraction or repulsion between two electrically charged particles. It states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

What factors affect the strength of the force according to Coulomb's Law?

The strength of the force between two charged particles is affected by the magnitude of the charges and the distance between them. The force increases as the charges increase and decreases as the distance between them increases.

How is Coulomb's Law related to Newton's Law of Universal Gravitation?

Just as Newton's Law of Universal Gravitation describes the force of attraction between two masses, Coulomb's Law describes the force of attraction or repulsion between two charged particles. Both laws follow the same inverse square relationship and are fundamental laws of physics.

How do you calculate the approximate force using Coulomb's Law?

The approximate force can be calculated by multiplying the magnitude of the two charges and dividing by the square of the distance between them. This can be expressed as F = k(q1q2)/r^2, where F is the force, k is the proportionality constant, q1 and q2 are the charges, and r is the distance between them.

What is the SI unit used to measure the force in Coulomb's Law?

The SI unit used to measure the force in Coulomb's Law is Newtons (N). This unit is equivalent to kg*m/s^2 and is used to measure all types of forces in physics.

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