- #1
shamieh
- 539
- 0
Count the number of strings of length $8$ over $A = \{w, x, y, z\}$ that begins with either $w$ or $y$
and have at least one $x$
I don't understand this question at all. First of all, this is a set A that contains 4 elements $w,x,y,z$ correct? They are asking me to count the number of strings of length 8? None of these are length 8, what are they asking me? Also wouldn't this be:
$A = \{ wxyz, wzxy, wyxz, ... \}$ I mean I'm going to have a lot of different combinations right? Also, every single group contained in the set is going to have at least one $x$.. I am so confused here.
and have at least one $x$
I don't understand this question at all. First of all, this is a set A that contains 4 elements $w,x,y,z$ correct? They are asking me to count the number of strings of length 8? None of these are length 8, what are they asking me? Also wouldn't this be:
$A = \{ wxyz, wzxy, wyxz, ... \}$ I mean I'm going to have a lot of different combinations right? Also, every single group contained in the set is going to have at least one $x$.. I am so confused here.