Counting problem involving numbered cards

In summary, to solve for ii (b), we need to list all possible combinations of three numbers from a set of nine, and then count how many of those numbers fall between 200 and 300. The answer is 22.
  • #1
Milly
21
0
How to solve ii (b) ? Thanks in advance.
 

Attachments

  • image.jpg
    image.jpg
    30.5 KB · Views: 79
Mathematics news on Phys.org
  • #2
Hello, Milly! :D

I have given your thread a title that briefly describes the posted problem. A title like "Help :/" does not tell anyone viewing the thread listing anything about the nature of the question being asked, and it is assumed that help is being sought.

Can you post what you have tried so far, so that our helpers can see where you are stuck, or where you may be going wrong, and can offer better assistance?

Using good thread titles and showing effort are two of the things we ask from our users, as given in our http://mathhelpboards.com/rules/.
 
  • #3
I actually tried out by using 5P2 but it didn't work.
 
  • #4
Hello, Milly!

How to solve ii (b)?

7. Nine cards are numbered: 1, 2, 2, 3, 3, 4, 6, 6, 6.

(ii) Three of the nine cards are chosen and placed in a line,
. . .making a 3-digit number.

Find how many different numbers can be made in this way
(b) if the number is between 200 and 300.

The easiest solution is to simply list them.

. . [tex]\begin{array}{ccccc} 212 & 221 & 231 & 241 & 261 \\ 213 & 223 & 232 & 242 & 2 62 \\ 214 & 224 & 233 & 243 & 263 \\ 216 & 226 & 234 & 2 46 & 264 \\ && 236 && 266 \end{array}[/tex]

Answer: 22
 
  • #5


To solve ii (b), we need to first understand what the question is asking. It is likely that the question is referring to a specific problem involving numbered cards, and ii (b) is a specific part or sub-problem of that larger problem.

To solve this specific part, we would need to gather all the necessary information and variables, such as the number of cards involved, the range of numbers on the cards, and any other given constraints or rules. Then, we would need to apply a counting strategy or formula to determine the total number of possible outcomes for this specific part.

It is difficult to provide a specific solution without more context or information about the problem. However, some common counting strategies that could be used to solve ii (b) include permutations, combinations, and the multiplication principle.

In general, when faced with a counting problem involving numbered cards, it is important to carefully read and understand the question, identify all relevant variables and constraints, and then apply a suitable counting strategy to find the solution.
 

FAQ: Counting problem involving numbered cards

How many ways can you arrange a deck of 52 numbered cards?

This is a classic counting problem known as the "permutation of n objects". The answer is 52!, which is equivalent to 8.0658 x 10^67.

If I have a hand of 5 cards, what is the probability of getting a flush (5 cards of the same suit)?

The probability of getting a flush is 0.00198079 or approximately 0.2%. This can be calculated by dividing the number of possible flush hands (4 x 13 = 52) by the total number of 5-card hands (52 choose 5 = 2,598,960).

How many different poker hands can be made with a deck of 52 cards?

There are 2,598,960 different 5-card hands that can be made with a deck of 52 cards. This is known as the "combinations of n objects".

How many ways can you deal a bridge hand (13 cards) from a deck of 52 cards?

The number of ways to deal a bridge hand is 52 choose 13, which is equivalent to 635,013,559,600. This is also known as the "combinations of n objects".

In a game of blackjack, what is the probability of getting a blackjack (an ace + a face card or a 10)?

The probability of getting a blackjack is approximately 0.024, or 2.4%. This can be calculated by dividing the number of possible blackjack hands (64) by the total number of 2-card hands (52 choose 2 = 1,326).

Similar threads

Replies
7
Views
3K
Replies
3
Views
4K
Replies
6
Views
2K
Replies
6
Views
3K
Replies
1
Views
637
Replies
1
Views
1K
Back
Top