- #1
harpazo
- 208
- 16
Find the critical points and test for relative extrema. List the critical points for which the Second Partials Test fails.
f (x, y) = x^3 + y^3
Solution:
f_x = 3x^2
f_y = 3y^2
f_xx = 6x
f_th = 6y
f_2xy = 0
I set f_x and f_y = 0 and found the critical points to be
(0, 0).
Is this right so far?
d = (6x)(6y) - [0]^2
d = 36xy
d = 36 (0)(0) - 0
d = 0
Since d = 0, the test is inconclusive.
I evaluated f (x, y) at (0, 0) and found the point in space to be (0, 0, 0).
The textbook goes on to say that the test for relative extrema fails and that we have a saddle point here.
1. Why does the test fails here?
2. I am not too sure how to show that we have a saddle point in this case.
Can someone explain this question in simple terms?
f (x, y) = x^3 + y^3
Solution:
f_x = 3x^2
f_y = 3y^2
f_xx = 6x
f_th = 6y
f_2xy = 0
I set f_x and f_y = 0 and found the critical points to be
(0, 0).
Is this right so far?
d = (6x)(6y) - [0]^2
d = 36xy
d = 36 (0)(0) - 0
d = 0
Since d = 0, the test is inconclusive.
I evaluated f (x, y) at (0, 0) and found the point in space to be (0, 0, 0).
The textbook goes on to say that the test for relative extrema fails and that we have a saddle point here.
1. Why does the test fails here?
2. I am not too sure how to show that we have a saddle point in this case.
Can someone explain this question in simple terms?