Cross product in spherical coordinates.

In summary, the conversation was about solving for the magnetic torque exerted by a circular loop on a square loop at a certain distance. The solution involved using a dipole approximation and converting the expression for the magnetic field B1 from spherical to Cartesian coordinates. Possible mistakes that may have resulted in an incorrect answer were identified and corrected.
  • #1
mancini0
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Homework Statement



i am trying to solve for the magnetic torque a circular loop of radius R exerts on a square loop of side length b a distance r away. The circular loop has a normal vector towards the positive z axis, the square loop has a normal towards the +y axis. The current is I in both loops.(Griffiths question 6.1)

Homework Equations


I used a dipole approximation and found the magnetic vector potential of the circular loop. I then took the curl of this in spherical coordinates and found an expression for B1, the magnetic field due to the loop. I know the torque exerted on the square loop is m2 X B1, where m2 is the magnetic dipole moment of the square (m2 = Ib^2 y)

The Attempt at a Solution


B1 = curl(A) =( u_0(m1) /(4 *pi* r^3) ) {2cosθ r + sinθ vartheta }
m1 = I(pi)R^2 z.

In order to take the curl, I switched B1 to cartesian coordinates. This is where I believed i made my mistake... I just used the following relationships:
x = Rcos[itex]\phi[/itex]sin[itex]\theta[/itex]
(for r I used the r component of B1, that is, R = u_0(m1) /(4 *pi* r^3) ) *2cosθ )
[itex]\phi [/itex] is 0 here because there is no [itex]\phi[/itex] component of B1.

y = 0 since sin([itex]\phi[/itex] is 0.

z = R cos [itex]\vartheta[/itex]

Now i just cross m2 = <0,Ib^2,0> with B1 using its components found above. However, my answer is incorrect. (The book uses the coordinate free form of B_dip in its solution, but I am trying to understand how to convert my expression for B1 from spherical to Cartesian coordinates.
 
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  • #2


Hello! Your approach seems to be on the right track. However, there are a few things that may have caused your incorrect answer.

First, when you converted B1 to Cartesian coordinates, you used the r component of B1, but you should have used the theta component since you are taking the cross product with m2 which has a y component. This would give you a different expression for B1 in Cartesian coordinates.

Second, when taking the cross product, make sure you are using the correct order of the vectors. In this case, you should be taking the cross product of m2 with B1, not the other way around.

Finally, make sure you are using the correct units for all your quantities. The magnetic dipole moment m2 should have units of A*m^2, and the magnetic field B1 should have units of T. Double check your units to make sure they all match up correctly.

I hope this helps! Keep up the good work.
 

FAQ: Cross product in spherical coordinates.

1. What is the cross product in spherical coordinates?

The cross product in spherical coordinates is a mathematical operation that determines the vector perpendicular to two given vectors in a 3-dimensional space. It is represented by the symbol "x" and is also known as the vector product.

2. How is the cross product calculated in spherical coordinates?

The cross product in spherical coordinates is calculated by taking the determinant of a 3x3 matrix. The first row contains unit vectors in the direction of the x, y, and z axes respectively. The second row contains the unit vectors in the direction of the spherical coordinates ρ, θ, and φ. The third row contains the unit vectors in the direction of the radial, azimuthal, and polar components of the cross product respectively.

3. What is the physical significance of the cross product in spherical coordinates?

The cross product in spherical coordinates has several physical applications, such as calculating torque and angular momentum in physics, and determining the direction of forces in mechanics and engineering. It is also used in computer graphics to calculate lighting and shading effects.

4. Can the cross product be expressed in terms of spherical coordinates?

Yes, the cross product can be expressed in terms of spherical coordinates by using the spherical basis vectors. These vectors are defined in terms of the unit vectors in the direction of the spherical coordinates ρ, θ, and φ. By using these basis vectors, the cross product can be written in terms of the radial, azimuthal, and polar components.

5. How does the cross product in spherical coordinates differ from the cross product in Cartesian coordinates?

The cross product in spherical coordinates and Cartesian coordinates differ in terms of the coordinate systems used. In spherical coordinates, the vectors are defined in terms of a radial distance, an angle from the z-axis, and an angle from the x-axis. In Cartesian coordinates, the vectors are defined in terms of the x, y, and z axes. Additionally, the formulas for calculating the cross product differ between the two coordinate systems.

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